A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 1.7 minutes and that the population of times is normally distributed. 12 7 8 12 7 8 11 6 9 7 7 9 9 10 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (7.9, 9.4). (Round to one decimal place as needed.) The 99% confidence interval is ). (Round to one decimal place as needed.) ■■ 4 √₁ Vi (1,1) More X
A publisher wants to estimate the mean length of time (in minutes) all adults spend reading newspapers. To determine this estimate, the publisher takes a random sample of 15 people and obtains the results below. From past studies, the publisher assumes o is 1.7 minutes and that the population of times is normally distributed. 12 7 8 12 7 8 11 6 9 7 7 9 9 10 Construct the 90% and 99% confidence intervals for the population mean. Which interval is wider? If convenient, use technology to construct the confidence intervals. The 90% confidence interval is (7.9, 9.4). (Round to one decimal place as needed.) The 99% confidence interval is ). (Round to one decimal place as needed.) ■■ 4 √₁ Vi (1,1) More X
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter10: Statistics
Section10.4: Distributions Of Data
Problem 19PFA
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