A psychiatrist devised a short screening test for depression. An independent blind comparisonwas made with a gold standard for diagnosis of depression among 215 psychiatric outpatients.Among the 69 outpatients found to be depressed according to the gold standard, 44 patientswere positive for the test. Among 146 patients found not to be depressed according to the goldstandard, 39 patients were found to be positive for the test.1. False-negative error rate2. False-positive error rate3. Positive predictive value4. Negative predictive value5. Positive likelihood ratio (Use the already rounded-off answers when6. Negative likelihood ratio (Use the already rounded-off answers whencomputing)computing)

“Since you have posted a question with multiple sub-parts, we will solve first three sub-parts for…

Answered: A psychiatrist devised a short…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Similar questions

What is difference between type 1 and type 2 errors?
Researchers were interested in assessing whether stress levels are different at the beginning of the semester compared to finals week. To test this, stress was measured in 5 students at the start of the semester and then again at the end of the semester during finals week. Participant Stress 1 Stress 2 Difference Score (Di) (Di - Mdiff)2 1 22 22 0 2 32 34 -2 3 24 25 -1 4 28 30 -2 5 26 29 -3 What is the observed test statistic (i.e., tobs)? Round to 2 decimal places.
Identify the P-value. What is the conclusion for this test?
The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 77% of all fatally injured automobile drivers were intoxicated. A random sample of 53 records of automobile driver fatalities in a certain county showed that 33 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 77% in Kit Carson County? Use a = 0.01. (a) What is the level of significance? State the null and alternate hypotheses. O Ho: p = 0.77; H1: p = 0.77 O Ho: p 0.77 O Ho: p = 0.77; H1: p 5 and ng > 5. O The standard normal, since np > 5 and ng > 5. The Student's t, since np < 5 and nq < 5. O The standard normal, since np < 5 and ng < 5. What is the value of the sample test statistic? (Round your answer to two decimal places.) (c) Find the P-value of the test statistic. (Round your answer to four decimal places.)
According to a survey conducted by the Association for Dressing and Sauces, 85% of American adults eat salad at least once a week. A nutritionist suspect that the percentage is higher that this. She conducts a survey of 200 American adults an finds that 171 of them eat salad at least once a week. Conduct the appropriate test that addresses the nutritionist's suspicions. Use the a = 0. 1 level of significance. What is the p-value? 0.85 0.855 0.1980 0.4215
Suppose your null hypothesis is that engineering majors earn more than $80,000. Further, researchers collect and analyze sample data that leads them to fail to reject this null hypothesis. However, in the population, it is true that engineering majors earn less than $80,000. What would we call this error? a. Type I error b. Type II error c. No error occured d. Error equal to the level of significance
The U.S. Department of Transportation, National Highway Traffic Safety Administration, reported that 75% of all fatally injured automobile drivers were intoxicated. A random sample of 52 records of automobile driver fatalities in a certain county showed that 33 involved an intoxicated driver. Do these data indicate that the population proportion of driver fatalities related to alcohol is less than 75% in Kit Carson County? Use ? = 0.10. (a) What is the level of significance? State the null hypothesis H0 and the alternate hypothesis H1 . H0 : p H1 : p (b) What sampling distribution will you use? The Student's tThe standard normal since np and nq What is the value of the sample test statistic? (Round your answer to two decimal places.) (c) Find the P-value of the test statistic. (Round your answer to four decimal places.) Sketch the sampling distribution and show the area corresponding to the P-value. A plot of…
The mean age of bus drivers in chicago is 56.7 years. If a hypothesis test is performed, how should you interpret a decision that rejects the null hypothesis?
A professional marketing survey involves product recognition in New York and California. Of 558 New York residents surveyed, 193 knew the product while 179 out of 614 Californians knew the product. 1. Test the claim that the recognition rates are greater in New York. 2. In which state does the product need the most help with name recognition? Use the given data to compare mean age of residents in Seaside and Marina. Sample Data * = 43.2 yr s = 4.7 yr n = 97 Seaside Before After 1. Test the claim that the mean age of seaside residents is equal to the mean age of Marina residents. 2. How would the result change if we use a = 0.01? Matched Pairs: Write the alternative hypothesis H₁, for each claim: 1. New engine management software will increase the gas mileage in your car. 2. My coaching will reduce your golf score. Difference An instructor gives a test before and after a lesson with these results from randomly selected students Before and After Data 54 70 = 61 Marina 56 s = 6.7 year…

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