(a) Prove that () = 1, (n) = 1, and (^)= (₁ = ¹) + n if 1≤k ≤n-1. (b) Use part (a) and induction to prove that (2) is a positive integer for all n, k = Z such that 0≤ k ≤n. (c) Let x, y E R. Prove that for every integer n ≥ 0, n (x + y)² = Σ (1) xn-kyk, k=0
(a) Prove that () = 1, (n) = 1, and (^)= (₁ = ¹) + n if 1≤k ≤n-1. (b) Use part (a) and induction to prove that (2) is a positive integer for all n, k = Z such that 0≤ k ≤n. (c) Let x, y E R. Prove that for every integer n ≥ 0, n (x + y)² = Σ (1) xn-kyk, k=0
Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section10.4: Mathematical Induction
Problem 26E
Related questions
Question
![5. For n, k EZ such that 0 ≤ k ≤n, define
Note that, by convention, 0! = 1.
(a) Prove that (n)
=
n
k
1, (n) = 1,
1. and
=
n!
k! (n - k)!
(1) = (₁7¹) + (−¹)
k 1
if 1≤k ≤n-1.
(b) Use part (a) and induction to prove that () is a positive integer for all n, k € Z
such that 0
k <n.
(c) Let x, y E R.
Prove that for every integer n ≥ 0,
n
-Σ (1)
k
k=0
(x + y)² = Σ
xn-ky, k
kyk,](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd7626d59-6405-4948-a625-19aca32c9eb7%2F8818dc3a-67f7-408c-bfde-267cced7a408%2Fun0dfqr_processed.jpeg&w=3840&q=75)
Transcribed Image Text:5. For n, k EZ such that 0 ≤ k ≤n, define
Note that, by convention, 0! = 1.
(a) Prove that (n)
=
n
k
1, (n) = 1,
1. and
=
n!
k! (n - k)!
(1) = (₁7¹) + (−¹)
k 1
if 1≤k ≤n-1.
(b) Use part (a) and induction to prove that () is a positive integer for all n, k € Z
such that 0
k <n.
(c) Let x, y E R.
Prove that for every integer n ≥ 0,
n
-Σ (1)
k
k=0
(x + y)² = Σ
xn-ky, k
kyk,
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