H(n) = 2H(n − 1) + 1, n ≥ 2, H(1) = 1 ⇒ H(n) = 2" – 1↓ Using mathematical induction, verify that our closed form solution is correct.

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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**Recursive Formula and Closed Form Solution Verification**

Given the recursive equation:

\[ H(n) = 2H(n-1) + 1, \quad n \geq 2, \quad H(1) = 1 \]

we need to verify the closed form solution:

\[ H(n) = 2^n - 1 \]

**Task:**

Using mathematical induction, verify that our closed form solution is correct.

**Explanation:**

- **Base Case:** Check if the closed form is true for \( n = 1 \).
- **Inductive Step:** Assume it holds for some \( n = k \), that is, \( H(k) = 2^k - 1 \). Show it holds for \( n = k+1 \).
- Substitute \( H(k+1) = 2H(k) + 1 \) and use the induction hypothesis to find \( H(k+1) \).

This process ensures that the closed form solution matches the recursive formulation for all \( n \geq 1 \).
Transcribed Image Text:**Recursive Formula and Closed Form Solution Verification** Given the recursive equation: \[ H(n) = 2H(n-1) + 1, \quad n \geq 2, \quad H(1) = 1 \] we need to verify the closed form solution: \[ H(n) = 2^n - 1 \] **Task:** Using mathematical induction, verify that our closed form solution is correct. **Explanation:** - **Base Case:** Check if the closed form is true for \( n = 1 \). - **Inductive Step:** Assume it holds for some \( n = k \), that is, \( H(k) = 2^k - 1 \). Show it holds for \( n = k+1 \). - Substitute \( H(k+1) = 2H(k) + 1 \) and use the induction hypothesis to find \( H(k+1) \). This process ensures that the closed form solution matches the recursive formulation for all \( n \geq 1 \).
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