A proton traveling at 27.8° with respect to the direction of a magnetic field of strength 3.25 mT experiences a magnetic force of 8.93 × 10-17 N. Calculate (a) the proton's speed and (b) its kinetic energy in electron-volts. (a) Number i (b) Number i ! Units m/s Units eV
Q: A proton traveling at 26.6° with respect to the direction of a magnetic field of strength 3.10 mT…
A:
Q: A proton traveling at 20.4° with respect to the direction of a magnetic field of strength 2.83 mT…
A:
Q: A proton traveling at 28.7° with respect to the direction of a magnetic field of strength 3.23 mT…
A: The answers are below
Q: A proton traveling at 34.2° with respect to the direction of a magnetic field of strength 3.38 mT…
A: Given value--- angle = 34.2 degree. magnetic field = 3.38 mR. magnetic force = 6.40 × 10-17 N. We…
Q: A proton traveling at 21.8° with respect to the direction of a magnetic field of strength 3.43 mT…
A:
Q: A proton traveling at 24.6° with respect to the direction of a magnetic field of strength 2.50 mT…
A: Magnetic field B = 2.50 mT = 2.50 × 10- 3 T Magnetic force F = 6.36 ×10- 17 N Velocity angle with…
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.38 T. If the…
A: (a) speed of the electron
Q: A proton traveling at 32.5° with respect to the direction of a magnetic field of strength 3.51 mT…
A: Given B= 3.51 mT F= 5.71 x 10-17 N angle between the direction of V and B = 32.50 mass of…
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.265 T. If the…
A: Given: B= 0.265 T E= 3.80×10-19 J R=? m= 9.1×10-31 kg a) E= 12mv2 Rearrange it for V V=…
Q: A proton traveling at 20.0° with respect to the direction of a magnetic field of strength 3.29 mT…
A: It is given that a proton traveling at 20.0° with respect to the direction of a magnetic field of…
Q: A proton traveling at 27.4° with respect to the direction of a magnetic field of strength 3.78 mT…
A:
Q: A proton traveling at 24.0° with respect to the direction of a magnetic field of strength 2.72 mT…
A: Angle made by the proton with respect to the direction of magnetic field (θ) = 24omagnetic field…
Q: A 5.47 C point charge is moving with a speed of 6.98 m/s. It is moving perpendicular to a magnetic…
A: Charge (q) = 5.47 C Speed (v) = 6.98 m/s Magnetic field (B) = 6.28 T
Q: 9 stones wheh look o feel dentcal. One of them a valuable gem north #250,000 and is actuially…
A:
Q: A proton traveling at 31.5° with respect to the direction of a magnetic field of strength 3.43 mT…
A: Given,B=3.43 mTF=9.69×10-17Nθ=31.5°
Q: A proton traveling at 28.7° with respect to the direction of a magnetic field of strength 3.23 mT…
A:
Q: A proton traveling at 18.6° with respect to the direction of a magnetic field of strength 2.88 mT…
A: The angle at which the proton travels is given as, θ=18.6o. The strength of the magnetic field is…
Q: A proton traveling at 28.3° with respect to the direction of a magnetic field of strength 2.48 mT…
A: We use F = qvBsinθ to get, v=FqBsinθ and, E = 12mv2
Q: A negatively charged ion with an excess electron moving with a velocity vx = 1.095 x103 m/s is…
A:
Q: A proton traveling at 27.7° with respect to the direction of a magnetic field of strength 3.00 mT…
A: This is a problem of Moving charged particle inside magnetic field. Please have a good look
Q: Calculate the resistivity of a material of a wire 10 m long. 0.2 mm in diameter and having a…
A:
Q: A proton traveling at 21.2° with respect to the direction of a magnetic field of strength 3.61 mT…
A:
Q: A proton traveling at 18.6° with respect to the direction of a magnetic field of strength 2.84 mT…
A:
Q: A proton traveling at 22.9° with respect to the direction of a magnetic field of strength 2.41 mT…
A:
Q: A proton traveling at 31.9° with respect to the direction of a magnetic field of strength 3.30 mT…
A:
Q: A proton traveling at 20.8° with respect to the direction of a magnetic field of strength 3.12 mT…
A:
Q: A proton traveling at 21.1° with respect to the direction of a magnetic field of strength 3.78 mT…
A:
Q: An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.300 T. If the…
A:
Q: A proton traveling at 26.6° with respect to the direction of a magnetic field of strength 3.62 mT…
A:
Q: A proton traveling at 20.0° with respect to the direction of a magnetic field of strength 3.29 mT…
A:
Q: A proton moving perpendicular to a magnetic field of strength 3.2 mT experiences a force due to the…
A: proton is moving perpendicular which means angle θ =900 Force F =6.0 × 10-21 N Magnetic field B =3.2…
Q: A proton traveling at 32.9° with respect to the direction of a magnetic field of strength 2.27 mT…
A:
Q: roton traveling at 31.6° with respect to the direction of a magnetic field of strength 3.49 mT…
A:
Q: A proton traveling at 17.3° with respect to the direction of a magnetic field of strength 3.49 mT…
A:
Q: A proton traveling at 33.3° with respect to the direction of a magnetic field of strength 3.14 mT…
A: θ = 33.3oB = 3.14 mT F = 6.73×10-17 N
Q: A proton traveling at 19.2° with respect to the direction of a magnetic field of strength 3.00 mT…
A: Given data: Angle between velocity and magnetic field (θ) = 19.2° Magnetic field (B) = 3.00 mT =…
Q: A proton traveling at 27.4° with respect to the direction of a magnetic field of strength 3.78 mT…
A:
Q: A proton traveling at 25.5° with respect to the direction of a magnetic field of strength 3.48 mT…
A:
Q: A proton traveling at 24.2° with respect to the direction of a magnetic field of strength 2.22 mT…
A:
Q: A proton traveling at 23.9 degrees with respect to the direction of a magnetic field of strength…
A: a. the force due to magnetic field can be expressed as
Q: A proton traveling at 26.0° with respect to the direction of a magnetic field of strength 2.94 mT…
A:
Step by step
Solved in 3 steps with 1 images