-119A proton of charge 1.6× 10- [C] ismoving with a speed of 1.6 × 10³ [m/s] as shownin the figure. At the instant when the protonis located at the position (x = 4; y = 0; z = 0) [m],what is the magnetic field produced by the protonat the origin?y [m]OB[T]v=+Protonx [m]= (0) + (1.6× 10-24) Ĵ + (0) ^ [T](0)+(1.6x10-24)+(1.6x10-24) kOB (0) + (0) + (1.6× 10-24) [T]=B = (1.6x 10-24)i + (0) + (1.6× 10-24) k[T]OB=(1.6x 10-24) + (0) Ĵ + (0) ^ [T]

Given: The charge of the proton is q = 1.6 x 10-19 C The velocity of the moving proton is v→ = 1.6 ×…

Answered: A proton of charge 1.6× 10-19 [C] is…

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