- A proton moves with a velocity of 100000 m/s in a region in which the magnetic field is 2 T. What is the magnitude of the magnetic force this charge experiences?
- A proton moves with a velocity of 100000 m/s in a region in which the magnetic field is 2 T. What is the magnitude of the magnetic force this charge experiences?
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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![**Problem Statement:**
A proton moves with a velocity of 100,000 m/s in a region where the magnetic field is 2 T (Tesla). What is the magnitude of the magnetic force this charge experiences?
**Concept Explanation:**
To solve this problem, we need to apply the formula for the magnetic force acting on a charged particle moving through a magnetic field:
\[ F = q \times v \times B \times \sin(\theta) \]
Where:
- \( F \) is the magnetic force,
- \( q \) is the charge of the particle (for a proton, \( q = 1.6 \times 10^{-19} \) C),
- \( v \) is the velocity of the particle (100,000 m/s in this case),
- \( B \) is the magnetic field strength (2 T here),
- \( \theta \) is the angle between the velocity vector and the magnetic field (assuming 90 degrees here for maximum force, so \( \sin(90^\circ) = 1 \)).
**Calculation:**
Substituting the known values into the formula:
\[ F = (1.6 \times 10^{-19} \, \text{C}) \times (100,000 \, \text{m/s}) \times (2 \, \text{T}) \]
\[ F = 3.2 \times 10^{-14} \, \text{N} \]
Therefore, the magnitude of the magnetic force experienced by the proton is \( 3.2 \times 10^{-14} \, \text{newtons (N)} \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F183a4de2-60b8-4988-9fb9-0a70f8d6fd02%2Febf09ed4-3944-449f-86e4-60e1213106b3%2F6nu1udw_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
A proton moves with a velocity of 100,000 m/s in a region where the magnetic field is 2 T (Tesla). What is the magnitude of the magnetic force this charge experiences?
**Concept Explanation:**
To solve this problem, we need to apply the formula for the magnetic force acting on a charged particle moving through a magnetic field:
\[ F = q \times v \times B \times \sin(\theta) \]
Where:
- \( F \) is the magnetic force,
- \( q \) is the charge of the particle (for a proton, \( q = 1.6 \times 10^{-19} \) C),
- \( v \) is the velocity of the particle (100,000 m/s in this case),
- \( B \) is the magnetic field strength (2 T here),
- \( \theta \) is the angle between the velocity vector and the magnetic field (assuming 90 degrees here for maximum force, so \( \sin(90^\circ) = 1 \)).
**Calculation:**
Substituting the known values into the formula:
\[ F = (1.6 \times 10^{-19} \, \text{C}) \times (100,000 \, \text{m/s}) \times (2 \, \text{T}) \]
\[ F = 3.2 \times 10^{-14} \, \text{N} \]
Therefore, the magnitude of the magnetic force experienced by the proton is \( 3.2 \times 10^{-14} \, \text{newtons (N)} \).
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