A proton moves through a uniform magnetic field given by B = (15.0î – 25.4ĵ + 12.7k) mT. At time t₁, the proton has a velocity given by ✓ = v¸î + vyĵ + (1.94 km/s)k and the magnetic force on the proton is F B = (5.33 × 10¯¹7 N)î + (3.15 × 10−¹7 N)Ĵ. (a) At that instant, what is v? (b) At that instant, what is vy? (a) Number (b) Number i Unit Unit

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Chapter1: Units, Trigonometry. And Vectors
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A proton moves through a uniform magnetic field given by \(\vec{B} = (15.0\hat{i} - 25.4\hat{j} + 12.7\hat{k}) \, \text{mT}\). At time \(t_1\), the proton has a velocity given by \(\vec{v} = v_x \hat{i} + v_y \hat{j} + (1.94 \, \text{km/s}) \hat{k}\) and the magnetic force on the proton is \(\vec{F}_B = (5.33 \times 10^{-17} \, \text{N}) \hat{i} + (3.15 \times 10^{-17} \, \text{N}) \hat{j}\).

**(a)** At that instant, what is \(v_x\)?

**(b)** At that instant, what is \(v_y\)?

Input boxes for the answers to parts (a) and (b) are provided with the following fields:

(a)  
- Number: [Input Box]
- Unit: [Dropdown Menu]

(b)  
- Number: [Input Box]
- Unit: [Dropdown Menu]
Transcribed Image Text:A proton moves through a uniform magnetic field given by \(\vec{B} = (15.0\hat{i} - 25.4\hat{j} + 12.7\hat{k}) \, \text{mT}\). At time \(t_1\), the proton has a velocity given by \(\vec{v} = v_x \hat{i} + v_y \hat{j} + (1.94 \, \text{km/s}) \hat{k}\) and the magnetic force on the proton is \(\vec{F}_B = (5.33 \times 10^{-17} \, \text{N}) \hat{i} + (3.15 \times 10^{-17} \, \text{N}) \hat{j}\). **(a)** At that instant, what is \(v_x\)? **(b)** At that instant, what is \(v_y\)? Input boxes for the answers to parts (a) and (b) are provided with the following fields: (a) - Number: [Input Box] - Unit: [Dropdown Menu] (b) - Number: [Input Box] - Unit: [Dropdown Menu]
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