A proton moves through a region containing a uniform electric field given by = 66.0 ĵ V/m and a uniform magnetic field = (0.200 î + 0.300 ĵ + 0.400 ) T. Determine the acceleration of the proton when it has a velocity = 230 î m/s
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A proton moves through a region containing a uniform electric field given by = 66.0 ĵ V/m and a uniform magnetic field = (0.200 î + 0.300 ĵ + 0.400 ) T. Determine the acceleration of the proton when it has a velocity = 230 î m/s
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- As shown in the figure, a small particle of charge q= 6.3 µ C and mass 3.84 x 1012 kg has velocity 9.0 x 10° m/s as it enters a region of uniform magnetic field. The particle is observed to travel in the semicircular path shown, with radius R= 5.0 cm. Calculate the magnitude and direction of the magnetic field in the region in T. If the field is into the page, give a negative number. If the field is out of the page, give a positive number. Region of magnetic field R Path of the particleAn proton moves with a speed of 5.0 × 10^5 m/s along the +x-axis. It enters a region where there is a magnetic field of 3.0 T, directed in the y-axis. Calculate the magnitude of the acceleration of the proton. (q = 1.60 × 10~19 c, me1 = 1.67 × 1027 kg) O o m/s? O 1.3 x 1018 m/s² O 1.5x 1014 m/s² O 1.3 x 10-18 m/s² O 3.0 x 10-18 m/s²004 A long straight wire lies on a horizontal table and carries a current of 0.59 µA. A proton