A proton moves perpendicular to a uniform magnetic field B at a speed of 1.20 x 107 m/s and experiences an acceleration of 1.90 x 1013 m/s² in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field. magnitude direction |---Select--- V T
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A proton moves perpendicular to a uniform magnetic field at a speed of 1.20 107 m/s and experiences an acceleration of 1.90 1013 m/s2 in the positive x direction when its velocity is in the positive z direction. Determine the magnitude and direction of the field.
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- A proton moves perpendicularly to a uniform magnetic field at 3.0 ✕ 107 m/s and exhibits an acceleration of 1.0 ✕ 1013 m/s2 in the +x-direction when its velocity is in the +z-direction. Determine the magnitude and direction of the field.The solar wind is a thin, hot gas given off by the sun. Charged particles in this gas enter the magnetic field of the earth and can experience a magnetic force. Suppose a charged particle traveling with a speed of 7.26 x 106 m/s encounters the earth's magnetic field at an altitude where the field has a magnitude of 1.75 x 10-7 T. Assuming that the particle's velocity is perpendicular to the magnetic field, find the radius of the circular path on which the particle would move if it were (a) an electron and (b) a proton.An electron beam is directed horizontally into a region where there is both an electric field and a magnetic field. The electric field points upward with a magnitude EE = 2.9 N/C, as shown in the figure. While moving through the region, the electron beam remains directed in a straight, horizontal line with a speed of 460 m/s. 1.) Express the magnitude of the electric force using the electric field E and the elementary charge e. 2.) Calculate the numerical value of the magnitude of the electric force in newtons. 3.) Express the magnitude of the magnetic force in terms of the elementary charge ee, electron speed vv, and BB, the magnitude of the magnetic field. 4.) If the electron is continuing in a horizontal straight line, express the magnitude of the magnetic field in terms of vv and EE, B = ? 5.) Calculate the magnitude of the magnetic field in tesla, if the electron continues in a horizontal straight line. 5.)
- A particle with positive charge q = 3.52 x 1018 C moves with a velocity v = (5î + 4ĵ – k) m/s through a region where both a uniform magnetic field and a uniform electric field exist. (a) Calculate the total force on the moving particle, taking B = (3î + 2ĵ + k) T and E = (3î - j - 2k) V/m. (Give your answers in N for each component.) Ey = Ey = F, = (b) What angle does the force vector make with the positive x-axis? (Give your answer in degrees counterclockwise from the +x-axis.) ° counterclockwise from the +x-axis (c) What If? For what vector electric field would the total force on the particle be zero? (Give your answers in V/m for each component.) E, = V/m E, = V/m E, = V/mProblem 2: = A particle with charge +2.0 C moves through a uniform magnetic field. At one instant the velocity vector is v (2î+4ĵ + 6k) m/sec and the magnetic force on the particle is F = (41-20ĵ+ 12k) N. The x and y components of the magnetic field are equal (Bx = By). Thus, the magnetic field is given by B = B×î + B×ĵ + B₂k. What are B× and B₂? Answer: Bx = -3 T and B₂ = −4 T.A beryllium-9 ion has a positive charge that is double the charge of a proton, and a mass of 1.50 ✕ 10−26 kg. At a particular instant, it is moving with a speed of 5.10 ✕ 106 m/s through a magnetic field. At this instant, its velocity makes an angle of 62° with the direction of the magnetic field at the ion's location. The magnitude of the field is 0.220 T. (a) What is the magnitude of the magnetic force (in N) on the ion? N (b) What is the magnitude of the ion's acceleration (in m/s2) at this instant? m/s2
- A charge is moving perpendicular to a magnetic field and experiences a force whose magnitude is 2.15 × 10-3 N. If this same charge were to move at the same speed and the angle between its velocity and the same magnetic field were 26.0o, what would be the magnitude of the magnetic force that the charge would experience?004 A long straight wire lies on a horizontal table and carries a current of 0.59 µA. A protonA proton moves perpendicular to a uniform magnetic field at a speed of 2.30 107 m/s and experiences an acceleration of 2.70 1013 m/s2 in the positive x-direction when its velocity is in the positive z-direction. Determine the magnitude and direction of the field.