A proton moves 10.0 cm on a path parallel to the direction of a uniform electric field of strength 3.0 N/C. What is the change in electrical potential energy? O-1.4 x 10^-20 J O-7.7 x 10^-20 J O-4.8 x 10^-20 J O-3.7 x 10^-20 J -8.4 x 10^-20 J

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A proton moves 10.0 cm on a path parallel to the direction of a uniform electric field of strength 3.0 N/C.
What is the change in electrical potential energy?
-1.4 x 10^-20 J
O -7.7 x 10^-20 J
O-4.8 x 10^-20 J
O-3.7 x 10^-20 J
-8.4 x 10^-20 ]
Transcribed Image Text:A proton moves 10.0 cm on a path parallel to the direction of a uniform electric field of strength 3.0 N/C. What is the change in electrical potential energy? -1.4 x 10^-20 J O -7.7 x 10^-20 J O-4.8 x 10^-20 J O-3.7 x 10^-20 J -8.4 x 10^-20 ]
Expert Solution
Step 1

Given:

The strength of the electric field is 3 N/C.

The distance traveled by the proton in the electric field direction is 10 cm.

 

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