A proton is moving with velocity v = (vy î + v, k) m/s, where vy = 6.60 x 105 and v, = 5.90 x 105. The instant it enters a uniform magnetic field it experiences a magnetic force in the positive y-direction of 2.80 x 10-5 N. [Charge of proton q = 1.602 x 10-19 c.]To begin, compose an equality for this problem given Fg = q vxB, such that each of the vectors is expressed as a vector sum of perpendicular (x/y/z) components. For example, B = B,î + B,ĵ + B,K.%3Da.) If there is no x-component of the magnetic field (B, = 0), what is the y-component of the magnetic field?By =b.) What is the magnitude and direction of the z-component of the magnetic field?E, =v k)

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A proton is moving with velocity v= (v, i + v, k) m/s, where vy = 6.60 x 105 and v, = 5.90 x 105. The instant it enters a uniform magnetic field it experiences a magnetic force in the positive y-direction of 2.80 x 105 N. [Charge of proton q = 1.602 x 1019 C.] To begin, compose an equality for this problem given Fg = q v»B, such that each of the vectors is expressed as a vector sum of perpendicular (x/y/z) components. For example, B = B,i + B, + B,k. a.) If there is no x-component of the magnetic field (B, = 0), what is the y-component of the magnetic field? By = b.) What is the magnitude and direction of the z-component of the magnetic field? |× - k)

A proton is moving with velocity v= (v, i + v, k) m/s, where vy = 6.60 x 105 and v, = 5.90 x 105. The instant it enters a uniform magnetic field it experiences a magnetic force in the positive y-direction of 2.80 x 105 N. [Charge of proton q = 1.602 x 1019 C.] To begin, compose an equality for this problem given Fg = q v»B, such that each of the vectors is expressed as a vector sum of perpendicular (x/y/z) components. For example, B = B,i + B, + B,k. a.) If there is no x-component of the magnetic field (B, = 0), what is the y-component of the magnetic field? By = b.) What is the magnitude and direction of the z-component of the magnetic field? |× - k)

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Magnetic Field Of Coaxial Cable

The word coaxial means same axis. So for a long straight cable to be coaxial, it must have concentric cylindrical shaped conductor around it. Coaxial cable (popularly called ‘coax’) has various applications ranging from current conductors to radiofrequency signal transmitters. This cable has lower emission losses and provides protection from electromagnetic interference which allows signals with less power to transmit over longer distances.For example, currents produced in the pickup of a stereo turntable generally travel to the amplifier through a coaxial cable.The self-inductance of a coaxial cable is another important characteristic, because it influences the propagation of electrical signals in the cable.

Question

A proton is moving with velocity v = (vy î + v, k) m/s, where vy = 6.60 x 105 and v, = 5.90 x 105. The instant it enters a uniform magnetic field it experiences a magnetic force in the positive y-direction of 2.80 x 10-5 N. [Charge of proton q = 1.602 x 10-19 c.]
To begin, compose an equality for this problem given Fg = q vxB, such that each of the vectors is expressed as a vector sum of perpendicular (x/y/z) components. For example, B = B,î + B,ĵ + B,K.
%3D
a.) If there is no x-component of the magnetic field (B, = 0), what is the y-component of the magnetic field?
By =
b.) What is the magnitude and direction of the z-component of the magnetic field?
E, =
v k)

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