A proton initially has v = 6.0 î - 3.0 j + 4.0 k and then 4.0 s later has v = -3.0 î - 3.0 j + 4.0 k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aavg in unit-vector notation? m/s2 î + m/s? ĵ m/s² k + (b) For that 4.0 s, what are the magnitude and direction of aava? m/s? ° (from the +x axis in the xz plane)

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Chapter1: Units, Trigonometry. And Vectors
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A proton initially has v = 6.0 î - 3.0 ĵ + 4.0 k and then 4.0 s later has v = -3.0 î - 3.0 ĵ + 4.0 k (in meters per second).
(a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation?
m/s? î +
m/s? ĵ +
m/s² k
(b) For that 4.0 s, what are the magnitude and direction of aavg?
m/s?
° (from the +x axis in the xz plane)
Transcribed Image Text:A proton initially has v = 6.0 î - 3.0 ĵ + 4.0 k and then 4.0 s later has v = -3.0 î - 3.0 ĵ + 4.0 k (in meters per second). (a) For that 4.0 s, what is the proton's average acceleration aava in unit-vector notation? m/s? î + m/s? ĵ + m/s² k (b) For that 4.0 s, what are the magnitude and direction of aavg? m/s? ° (from the +x axis in the xz plane)
Expert Solution
Step 1

Given data

The velocity of the proton initially is vi=v=6i^-3j^+4k^

The velocity of the proton finally becomes is vf=v= -3 i^-3 j^+4 k^

The duration of the time is t = 4 s

 

 

 

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