A protein exists in a conformational equilibrium between a T conformation and an R conformation. See the linked functions diagram below showing H+ dissociation from a functional group on the protein in the T conformation and the same group on the protein in the R conformation. The proton equilibrium dissociation constant depends on which conformation (T or R) the protein is in. KTR T•H* R•H* Suppose that KTH+ = 2 x 10-7 M KTH KRH* KRH+ = 4 x 10-6 M KR K'TR = 5 x 10-3 T+ H* R+H* Note: The reactions are proceeding from the upper left to lower right. KTR = Equilibrium constant for T•H* -> R•H* = The [R•H*]/[T•H*] ratio with the group protonated. K'T TR = Equilibrium constant for T-> R = The [R] /[T] ratio with the group protonated. KTH+ = Equilibrium dissociation constant for proton dissociation from %3! the T conformation. KRH+ = Equilibrium dissociation constant for proton dissociation from the R conformation.
A protein exists in a conformational equilibrium between a T conformation and an R conformation. See the linked functions diagram below showing H+ dissociation from a functional group on the protein in the T conformation and the same group on the protein in the R conformation. The proton equilibrium dissociation constant depends on which conformation (T or R) the protein is in. KTR T•H* R•H* Suppose that KTH+ = 2 x 10-7 M KTH KRH* KRH+ = 4 x 10-6 M KR K'TR = 5 x 10-3 T+ H* R+H* Note: The reactions are proceeding from the upper left to lower right. KTR = Equilibrium constant for T•H* -> R•H* = The [R•H*]/[T•H*] ratio with the group protonated. K'T TR = Equilibrium constant for T-> R = The [R] /[T] ratio with the group protonated. KTH+ = Equilibrium dissociation constant for proton dissociation from %3! the T conformation. KRH+ = Equilibrium dissociation constant for proton dissociation from the R conformation.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Is this the correct answer of the protons bind?
![For this protein, protons bind more tightly to
neither state.
the T state.
the R state.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcaf61854-7522-4075-8af1-447956fb28ae%2Fc4e00b31-1ead-4700-93e8-928925a9dc2d%2Fsk6nxg4_processed.jpeg&w=3840&q=75)
Transcribed Image Text:For this protein, protons bind more tightly to
neither state.
the T state.
the R state.
![Linked functions
A protein exists in a conformational equilibrium between a T
conformation and an R conformation.
See the linked functions diagram below showing H+ dissociation from a
functional group on the protein in the T conformation and the same
group on the protein in the R conformation. The proton equilibrium
dissociation constant depends on which conformation (T or R) the
protein is in.
KTR
T•H*
R•H*
Suppose that
KTH+ = 2 x 10-7 M
KTH
KRH*
KRH+ = 4 x 10-6 M
%3D
KIR
K'TR = 5 x 10-3
%3D
T+H*
R+ H*
Note: The reactions are proceeding from the upper left to lower right.
KTR = Equilibrium constant for T•H* -> R•H* = The [R•H*]/ [T•H*] ratio
with the group protonated.
K'TR = Equilibrium constant for T-> R = The [R]/[T]ratio with the group
protonated.
KTH+ = Equilibrium dissociation constant for proton dissociation from
the T conformation.
KRH+ = Equilibrium dissociation constant for proton dissociation from
the R conformation.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcaf61854-7522-4075-8af1-447956fb28ae%2Fc4e00b31-1ead-4700-93e8-928925a9dc2d%2F75u7lfk_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Linked functions
A protein exists in a conformational equilibrium between a T
conformation and an R conformation.
See the linked functions diagram below showing H+ dissociation from a
functional group on the protein in the T conformation and the same
group on the protein in the R conformation. The proton equilibrium
dissociation constant depends on which conformation (T or R) the
protein is in.
KTR
T•H*
R•H*
Suppose that
KTH+ = 2 x 10-7 M
KTH
KRH*
KRH+ = 4 x 10-6 M
%3D
KIR
K'TR = 5 x 10-3
%3D
T+H*
R+ H*
Note: The reactions are proceeding from the upper left to lower right.
KTR = Equilibrium constant for T•H* -> R•H* = The [R•H*]/ [T•H*] ratio
with the group protonated.
K'TR = Equilibrium constant for T-> R = The [R]/[T]ratio with the group
protonated.
KTH+ = Equilibrium dissociation constant for proton dissociation from
the T conformation.
KRH+ = Equilibrium dissociation constant for proton dissociation from
the R conformation.
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