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3. (Balance this reaction In Basic Solution): 103 (aq) + Zn (s) → -1=15-2×3=-6 Zn²+ (aq) + (aq)

3. (Balance this reaction In Basic Solution): 103 (aq) + Zn (s) → -1=15-2×3=-6 Zn²+ (aq) + (aq)

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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37 2-8-18-8-1 32.906 Cs ➡ 18-8-1 2- 2-8 Sy a 19 2-8-8 85.4678 5R +1 (22L Chemistry - 2011 Edition A 88 -18-32-18 3. (Balance this reaction In Basic Solution): 103¯¯ (aq) + Zn (s) → -1=15-2×3=6 Ge (Zn (s) 0 -1 1 -66 + 6H² + 103 (14) I (4) + 3H₂O → Zn (uu) 2+ Ö SUB at the Zn²+ (aq) + I (aq) + 2e-¯)x3 2+ 32n (s) 32 (aq) + be 68² + 6H²+I03 (64) + 32M(5) → I (aq) + 3H₂O +3² (aa) +6e- 60H²+I03(aq) +3Zn(s) → I (14) + 3H₂0 + 3 Zn ((4) сии) 2+ کی کارا -1 20.180 10 2-8 39.948 Ar 0245 22 +2 Ne 4.00260 18 18 0 He
Transcribed Image Text:37 2-8-18-8-1 32.906 Cs ➡ 18-8-1 2- 2-8 Sy a 19 2-8-8 85.4678 5R +1 (22L Chemistry - 2011 Edition A 88 -18-32-18 3. (Balance this reaction In Basic Solution): 103¯¯ (aq) + Zn (s) → -1=15-2×3=6 Ge (Zn (s) 0 -1 1 -66 + 6H² + 103 (14) I (4) + 3H₂O → Zn (uu) 2+ Ö SUB at the Zn²+ (aq) + I (aq) + 2e-¯)x3 2+ 32n (s) 32 (aq) + be 68² + 6H²+I03 (64) + 32M(5) → I (aq) + 3H₂O +3² (aa) +6e- 60H²+I03(aq) +3Zn(s) → I (14) + 3H₂0 + 3 Zn ((4) сии) 2+ کی کارا -1 20.180 10 2-8 39.948 Ar 0245 22 +2 Ne 4.00260 18 18 0 He
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