A projectile is projected from the origin with a velocity of 30.0 m/s at an angle of 40.0 degrees above the horizontal. What is the time it takes the projectile to reach maximum height?   Multiple Choice   2.23 s   1.02 s   1.97 s   1.54 s   2.66 s

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A: initial velocity = V0 = 310 m/s angle = 58 time = t = 40 sec

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Q: To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of…

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A: Given, speed=42 m/s Angle=30 Wall is at 21 m Let the time of flight is T sec

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Q: To start an avalanche on a mountain slope, an artillery shell is fired with an initial velocity of…

A: S = u t +1/2 a t^2 apply this in x direction ( as no force in x direction so a=0) X = 350*cos(58)*36…

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Q: What is the angle of the initial velocity?  Enter units as 'degrees'

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Q: Answer part B). What total time is the object in the air for?

A: b) The expression for the time of flight in air is,

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A: Given : Horizontal distance =x=31m Vertical distance = y =2.4 m θ=27°

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Q: You launch a projectile with an initial speed of 48.7 m/s from the top of a building 42.5 m above…

A: Given information: Initial speed(vo)=48.7m/s height=42.5m  Angle=46.2degrees

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Projectile Motion