4. A projectile has an initial velocity of 20.0 m/s at an angle of 35.0° with respect to the x-direction. The object is initially 50.0 m above ground level. a) What is the maximum height of the object relative to the ground level? Vi= 20m is 30: 16.4mis 35° Vxi = 20 Cos (35) Vyi = 20 sin (35°) Vy=0 @ AYMAX Vyf? = Vyi"-2gay =11. Smis %3D %3D 50m 2. %3D hmax = 0=(11.5)²-29AY %3D = Aymax +h -13 2.25= - 29Ay %3D 6.75m + Som -132.25= AY 56.8 m 19.6 Ay = 6.75 m b) What total time is the object in the air for? Źğt²+ Vyit 2. Ay %3D - 56.8 = -gt 2. |1. 5t 11. 5t/s 9.9t+11.5t + 56.8=0 %3D A = -4.9 B = ||.5 C = 56.8 %3D %3D t= -|1.5t V(11.5)²_4(-4.9)(56.8) 21-4.9) t = - 11.5+ 13 2.25 + 1|1328 -11.5t -9.8 t = - 11. S t 35.292 4.773 t=7.478

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Distance and Speed

The speed, distance and time relation forms the basis of study of motion. You will need these concepts in the study of Mechanics. This concept is applicable for students who are studying the following courses –