A project with excavation and construction stages will take place at your site (below which lies a saturated clay layer). On March 1, the effective stress at point A (in the middle of the clay layer) is 65 kPa, and the overconsolidation ratio is 1.3. On April 1, the effective stress at point A is 40 kPa. On May 1, the effective stress at point A is 60 kPa. What is the overconsolidation ratio on May 1?

Structural Analysis
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ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
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## Geotechnical Engineering: Overconsolidation Ratio Calculation

**Use 10 kN/m³ for the unit weight of water.**

### Question 3

A project with excavation and construction stages will take place at your site (below which lies a saturated clay layer).

- **On March 1**, the effective stress at point A (in the middle of the clay layer) is 65 kPa, and the overconsolidation ratio is 1.3.
- **On April 1**, the effective stress at point A is 40 kPa.
- **On May 1**, the effective stress at point A is 60 kPa.

**Question:** What is the overconsolidation ratio on May 1?

[Answer Box]

### Explanation:

This problem involves calculating the overconsolidation ratio (OCR) for a given point in a saturated clay layer during different stages of your project. The overconsolidation ratio is a measure of the preloading of a soil, defined as:

\[ \text{OCR} = \frac{\sigma'_{\text{max}}}{\sigma'_0} \]

where:
- \(\sigma'_{\text{max}}\) is the maximum past effective stress the soil has experienced.
- \(\sigma'_0\) is the current effective stress.

To solve for the OCR on May 1:
1. Recognize that the maximum past effective stress (\(\sigma'_{\text{max}}\)) can be deduced from the initial conditions provided on March 1.
2. Use the current effective stress on May 1.

From March 1 data:
\[ \text{OCR} = \frac{\sigma'_{\text{max}}}{65 \text{ kPa}} = 1.3 \]
Thus:
\[ \sigma'_{\text{max}} = 1.3 \times 65 \text{ kPa} = 84.5 \text{ kPa} \]

On May 1, the effective stress (\(\sigma'_0\)) is given as 60 kPa.

Hence:
\[ \text{OCR on May 1} = \frac{84.5 \text{ kPa}}{60 \text{ kPa}} = 1.41 \]

**Answer: 1.41**

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Transcribed Image Text:--- ## Geotechnical Engineering: Overconsolidation Ratio Calculation **Use 10 kN/m³ for the unit weight of water.** ### Question 3 A project with excavation and construction stages will take place at your site (below which lies a saturated clay layer). - **On March 1**, the effective stress at point A (in the middle of the clay layer) is 65 kPa, and the overconsolidation ratio is 1.3. - **On April 1**, the effective stress at point A is 40 kPa. - **On May 1**, the effective stress at point A is 60 kPa. **Question:** What is the overconsolidation ratio on May 1? [Answer Box] ### Explanation: This problem involves calculating the overconsolidation ratio (OCR) for a given point in a saturated clay layer during different stages of your project. The overconsolidation ratio is a measure of the preloading of a soil, defined as: \[ \text{OCR} = \frac{\sigma'_{\text{max}}}{\sigma'_0} \] where: - \(\sigma'_{\text{max}}\) is the maximum past effective stress the soil has experienced. - \(\sigma'_0\) is the current effective stress. To solve for the OCR on May 1: 1. Recognize that the maximum past effective stress (\(\sigma'_{\text{max}}\)) can be deduced from the initial conditions provided on March 1. 2. Use the current effective stress on May 1. From March 1 data: \[ \text{OCR} = \frac{\sigma'_{\text{max}}}{65 \text{ kPa}} = 1.3 \] Thus: \[ \sigma'_{\text{max}} = 1.3 \times 65 \text{ kPa} = 84.5 \text{ kPa} \] On May 1, the effective stress (\(\sigma'_0\)) is given as 60 kPa. Hence: \[ \text{OCR on May 1} = \frac{84.5 \text{ kPa}}{60 \text{ kPa}} = 1.41 \] **Answer: 1.41** ---
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