A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test scoreof students in the morning classes. He collects data from a random sample of 150 students in evening classes and finds that they have a mean test score of 85.8. Heknows the population standard deviation for the evening classes to be 4.9 points. A random sample of 250 students from morning classes results in a mean test score of86.6. He knows the population standard deviation for the morning classes to be 2.7 points. Test his claim with a 90% level of confidence. Let students in the eveningclasses be Population 1 and let students in the morning classes be Population 2.Step 3 of 3: Draw a conclusion and interpret the decision.

To draw a conclusion and interpret the decision for the given hypothesis test, we need to follow…

Answered: A professor believes that, for the…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Imagine that every elementary school in California is measured on several characteristics and then given an overall Quality Score. In Los Angeles Unified School District, the schools have an average (mean) quality score of 101.8 with a standard deviation of 7.2. One school in Los Angeles, Carver Elementary, gets a quality score of 104.5. In San Francisco Unified School District, the schools have an average (mean) quality score of 102.3 with a standard deviation of 9.4. One school in San Francisco, Bryant Elementary, gets a quality score of 99.5. Find the Z-scores for both of these two schools (Carver Elementary in Los Angeles, and Bryant Elementary in San Francisco)
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 150 students in evening classes and finds that they have a mean test score of 88.8. He knows the population standard deviation for the evening classes to be 8.4 points. A random sample of 250 students from morning classes results in a mean test score of 89.9. He knows the population standard deviation for the morning classes to be 5.4 points. Test his claim with a 99% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 3 of 3 : Draw a conclusion and interpret the decision.
A professor is concerned that the two sections of college algebra that he teaches are not performing at the same level. To test his claim, he looks at the mean exam score for a random sample of students from each of his classes. In Class 1, the mean exam score for 1515 students is 81.281.2 with a standard deviation of 3.43.4. In Class 2, the mean exam score for 1818 students is 83.883.8 with a standard deviation of 5.95.9. Test the professor’s claim at the 0.100.10 level of significance. Assume that both populations are approximately normal and that the population variances are equal. Let Class 1 be Population 1 and let Class 2 be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to three decimal places.
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 76.8. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 77.8. He knows the population standard deviation for the morning classes to be 1.9 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
The state Government gives grants to low-income undergraduate students. According to the National Postsecondary Student Aid Study conducted by the U.S. Department of Education in 2008, the average Pell grant award for 2007-2008 was $2,600. We wonder if the mean amount is different this year for Pell grant recipients at San Jose State University. Suppose that we randomly select 50 Pell grant recipients from San Jose State University. For these 50 students, the mean Pell grant award is $2,450 with a standard deviation of $600. Let µ = the mean amount of Pell grant awards received by San Jose State University Pell grant recipients this year. We test the hypotheses: H0: μ = 2,600 , Ha: μ ≠ 2,600. The sample size is greater than 30, so a t-model is a good fit for the sampling distribution. What is the t-test statistic? What is the P-value?
Suppose the scores on a college entrance examination are normally distributed with a mean of 525 and a standard deviation of 110. A certain prestigious university will consider admission only for those applicants whose scores exceed the 95th percentile of the distribution. Find the minimum score an applicant must achieve in order to receive consideration for admission to the university. Round your answer up to the nearest integer.
Two friends, Karen and Jodi, work different shifts for the same ambulance service. They wonder if the different shifts average different numbers of calls. Looking at past records, Karen determines from a random sample of 39 shifts that she had a mean of 4.7 calls per shift. She knows that the population standard deviation for her shift is 1.5 calls. Jodi calculates from a random sample of 31 shifts that her mean was 5.4 calls per shift. She knows that the population standard deviation for her shift is 1.2 calls. Test the claim that there is a difference between the mean numbers of calls for the two shifts at the 0.02 level of significance. Let Karen's shifts be Population 1 and let Jodi's shifts be Population 2. Step 2 of 3 : Compute the value of the test statistic. Round your answer to two decimal places.
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 88.1. He knows the population standard deviation for the evening classes to be 4.2 points. A random sample of 150 students from morning classes results in a mean test score of 89.1. He knows the population standard deviation for the morning classes to be 7.7 points. Test his claim with a 95 % level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 2 of 3: Compute the value of the test statistic. Round your answer to two decimal places.
According to the U.S. Census, the average adult woman is the United States is 65 inches tall and the standard deviation is 3 inches. If Zsike is 67 inches tall, what is her z-score?
One year Terry had the lowest ERA (earned-run average, mean number of runs yielded per nine innings pitched) of any male pitcher at his school, with an ERA of 3.02. Also, Karen had the lowest ERA of any female pitcher at the school with an ERA of 3.24. For the males, the mean ERA was 4.364 and the standard deviation was 0.639. For the females, the mean ERA was 3.801 and the standard deviation was 0.959 Find their respective z-scores. Which player had the better year relative to their peers, Terry or Karen? (Note: In general, the lower the ERA, the better the pitcher.) Terry had an ERA with a z-score of Karen had an ERA with a z-score of (Round to two decimal places as needed) Which player had a better year in comparison with their peers? OA. Terry had a better year because of a higher z-score. OB. Karen had a better year because of a lower z-score. OC. Terry had a better year because of a lower z-score. O D. Karen had a better year because of a higher z-score. GIL
A professor believes that, for the introductory art history classes at his university, the mean test score of students in the evening classes is lower than the mean test score of students in the morning classes. He collects data from a random sample of 250 students in evening classes and finds that they have a mean test score of 76.8. He knows the population standard deviation for the evening classes to be 7.2 points. A random sample of 200 students from morning classes results in a mean test score of 77.8. He knows the population standard deviation for the morning classes to be 1.9 points. Test his claim with a 90% level of confidence. Let students in the evening classes be Population 1 and let students in the morning classes be Population 2. Step 1 of 3 : State the null and alternative hypotheses for the test. Fill in the blank below. H0: μ1=μ2 Ha: μ1__μ2
The U.S. Center for Disease Control reports that in year 1900, the mean life expectancy is 47.6 years for whites and 33 years for nonwhites. (Click here for reference data) Suppose a survey of randomly selected death records for white and nonwhite people born in 1900 from a certain county is conducted. Of the 110 whites surveyed, the mean life span was 48.2 years with a standard deviation of 11.2 years and of the 95 nonwhites, the mean life span was 39.3 years with a standard deviation of 16 years. Conduct a hypothesis test at the 0.05 level of significance to determine whether there was no difference in mean life spans in the county for whites and nonwhites in year 1900. Preliminary: Is it safe to assume thatnw≤5% of all white people born in 1900 andnnw≤5% of all nonwhite people born in 1900? No Yes Is nw≥30 and nnw≥30 ? No Yes Test the claim: Determine the null and alternative hypotheses. H0: μw μnw Ha: μw μnw Determine the test statistic. Round to four…

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