A problem about inductive or dense sets like that, if both A and B are inductive, then are An B and AUB also inductive? If both A and B are dense, then are An B and AUB also dense? Why? Problem 5

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Help me understand these two problems.

Problem 5
A problem about inductive or dense sets like that, if both A and B are inductive, then are
AnB and AU B also inductive? If both A and B are dense, then are AnB and AUB also dense? Why?
Transcribed Image Text:Problem 5 A problem about inductive or dense sets like that, if both A and B are inductive, then are AnB and AU B also inductive? If both A and B are dense, then are AnB and AUB also dense? Why?
Problem 2
: Important theorems and results such as
1. Principle of Mathematical Induction (Page 6)
2. Completeness Axiom (Page 8)
3. Theorem 1.5 Archimedean Property (Page 13)
4. Theorem 1.9 Density of rational numbers (Page 15)
5. Corollary 1.10 Density of irrational numbers (Page 15)
6. Theorem 1.11 Triangle Inequality (Page 17)
Transcribed Image Text:Problem 2 : Important theorems and results such as 1. Principle of Mathematical Induction (Page 6) 2. Completeness Axiom (Page 8) 3. Theorem 1.5 Archimedean Property (Page 13) 4. Theorem 1.9 Density of rational numbers (Page 15) 5. Corollary 1.10 Density of irrational numbers (Page 15) 6. Theorem 1.11 Triangle Inequality (Page 17)
Expert Solution
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Since you have asked multiple questions, we will solve the first Question for you. If you want any specific question to be solved, then please specify the question number or post only that question.

Given that the set A and B are inductive sets.

We know that a set X is an inductive set if:

  1. ϕX
  2. xX implies that xxX.

(a).

Consider the set AB.

Since A and B are inductive sets, therefore:

ϕA and ϕB, therefore ϕAB.

Suppose xAB, therefore either xA or xB.

Therefore without loss of generality let xA.

Since A is an inductive set, therefore xxA and hence xxAB.

Hence AB is an inductive set.

Consider the set AB.

Since A and B are inductive sets, therefore:

ϕA and ϕB, therefore ϕAB.

Suppose xAB, therefore xA and xB.

Since A is an inductive set and xA, therefore xxA and hence xxAB.

Hence AB is an inductive set.

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