A problem about inductive or dense sets like that, if both A and B are inductive, then are An B and AUB also inductive? If both A and B are dense, then are An B and AUB also dense? Why? Problem 5
Help me understand these two problems.
![Problem 5
A problem about inductive or dense sets like that, if both A and B are inductive, then are
AnB and AU B also inductive? If both A and B are dense, then are AnB and AUB also dense? Why?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F072e444d-1bde-4899-b3c3-9f07885f3d58%2Faedc4f40-e03d-46f2-8cc0-18c4790331e0%2Fwsioato_processed.png&w=3840&q=75)
![Problem 2
: Important theorems and results such as
1. Principle of Mathematical Induction (Page 6)
2. Completeness Axiom (Page 8)
3. Theorem 1.5 Archimedean Property (Page 13)
4. Theorem 1.9 Density of rational numbers (Page 15)
5. Corollary 1.10 Density of irrational numbers (Page 15)
6. Theorem 1.11 Triangle Inequality (Page 17)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F072e444d-1bde-4899-b3c3-9f07885f3d58%2Faedc4f40-e03d-46f2-8cc0-18c4790331e0%2F7k8a25_processed.png&w=3840&q=75)
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Since you have asked multiple questions, we will solve the first Question for you. If you want any specific question to be solved, then please specify the question number or post only that question.
Given that the set and are inductive sets.
We know that a set is an inductive set if:
- implies that .
(a).
Consider the set .
Since and are inductive sets, therefore:
and , therefore .
Suppose , therefore either or .
Therefore without loss of generality let .
Since is an inductive set, therefore and hence .
Hence is an inductive set.
Consider the set .
Since and are inductive sets, therefore:
and , therefore .
Suppose , therefore and .
Since is an inductive set and , therefore and hence .
Hence is an inductive set.
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