(а) Principal amount=$225 Rate of interest=D0.0625% Period= one year Number of instalment=12 Now, nt Amount = p × (1+ 5)* рx (1+ #)" 12t 0.0625 » A = 225 × (1+ 1 + → A = 225 x (1. 00 T2 » A(t 225(1. 00520)2 It is required in the exponential form y = a(b)".

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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For each of the scenarios in question 1 please determine: a) An acceptable domain and range b) The end behavior c) A sketch of the graph for each scenario I have question 1 answer below
(a)
Principal amount=$225
Rate of interest=0.0625%
Period= one year
Number of instalment=12
Now,
nt
Атount — р х (1+ #)"
p x (1+ 7)"
12t
0.0625
> A = 225 x (1+
→ A = 225 × (1. 00:
%3D
T2
→ A(t) = 225(1. 00520)*"
12t
It is required in the exponential form y = .
Transcribed Image Text:(a) Principal amount=$225 Rate of interest=0.0625% Period= one year Number of instalment=12 Now, nt Атount — р х (1+ #)" p x (1+ 7)" 12t 0.0625 > A = 225 x (1+ → A = 225 × (1. 00: %3D T2 → A(t) = 225(1. 00520)*" 12t It is required in the exponential form y = .
(b)
Original price of new vehicle=$39,525.
Rate of depreciation=12%=0.12
Period= one year
We need to find price after 1 year.
Now,
Furture value = original value × (1 – 0. 12)*
» F.V = 39, 525 × (0. 88)*
→ F.V = 39, 525(0. 88)'
It is required form in the exponential form
Y = a(b)ª
Transcribed Image Text:(b) Original price of new vehicle=$39,525. Rate of depreciation=12%=0.12 Period= one year We need to find price after 1 year. Now, Furture value = original value × (1 – 0. 12)* » F.V = 39, 525 × (0. 88)* → F.V = 39, 525(0. 88)' It is required form in the exponential form Y = a(b)ª
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