A potassium chloride solution that also contains 5% (m/V) dextrose is administered intravenously to treat some forms of malnutrition. The potassium ion concentration in this solution is 53 meq/L. Calculate the potassium ion concentration in moles/L. Enter your answer in the provided box.
A potassium chloride solution that also contains 5% (m/V) dextrose is administered intravenously to treat some forms of malnutrition. The potassium ion concentration in this solution is 53 meq/L. Calculate the potassium ion concentration in moles/L. Enter your answer in the provided box.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A potassium chloride solution that also contains 5% (m/V) dextrose is administered intravenously to treat some forms of malnutrition. The potassium ion concentration in this solution is 53 meq/L. Calculate the potassium ion concentration in moles/L. Enter your answer in the provided box.
[ ] M
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**Explanation:**
This exercise involves calculating the concentration of potassium ions (K⁺) in a solution. The given concentration is in milliequivalents per liter (meq/L), and you need to convert this to moles per liter (M).
To solve this problem, remember:
1. **Equivalence**: 1 meq/L of K⁺ equals 1 mmol/L because potassium has a valency of 1.
2. **Conversion**: 53 meq/L is equivalent to 53 mmol/L.
Therefore, the potassium ion concentration is 0.053 M (since 1 mmol/L = 0.001 mol/L).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F073eb5ef-2617-4d6f-9bce-a81ca84c4945%2F265e145e-807e-46b1-8585-4c05f8a7d8fe%2Fre60wi.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription for Educational Website**
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A potassium chloride solution that also contains 5% (m/V) dextrose is administered intravenously to treat some forms of malnutrition. The potassium ion concentration in this solution is 53 meq/L. Calculate the potassium ion concentration in moles/L. Enter your answer in the provided box.
[ ] M
---
**Explanation:**
This exercise involves calculating the concentration of potassium ions (K⁺) in a solution. The given concentration is in milliequivalents per liter (meq/L), and you need to convert this to moles per liter (M).
To solve this problem, remember:
1. **Equivalence**: 1 meq/L of K⁺ equals 1 mmol/L because potassium has a valency of 1.
2. **Conversion**: 53 meq/L is equivalent to 53 mmol/L.
Therefore, the potassium ion concentration is 0.053 M (since 1 mmol/L = 0.001 mol/L).
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