Answered: A positively charged particle Q, - +15…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

A positively charged particle Q, - +15 nC is held fixed at the
origin. A second charge Q2of mass m - 9.5 ug is located at a distance d - 25 cm directly above charge Q1. The net force on Q2, is equal to zero. You may assume this system
is close to the surface of the Earth.

Calculate the magnitude of O2 in units of nanocoulombs.

Expert Solution

Step 1

Given that,

$Q_{1} = 15 n C = 15 \times 10^{- 9} C$

Mass of the charge $Q_{2}$ is $m = 9.5 μ g = 9.5 \times 10^{- 9} k g$

Distance between two charges $d = 25 c m = 0.25 m$

Net force on the charge $Q_{2}$ is $0$ .

According to the question,

charge $Q_{2}$ is the located at a distance $d = 25 c m$ directly above charge $Q_{1}$ .

Since, net force on $Q_{2}$ is zero, electrostatic force due to $Q_{1}$ on $Q_{2}$ will act upwards i.e $Q_{2}$ is a positive charge.

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