A population of bacteria begins with 200000. The population is growing according to the Malthusian growth equation given by P'(t) = 0.028 P(t), where t is in minutes. Give the solution to this differential equation. P(t): Find how long it takes for this population to double. Doubles in min. Find the population after t P(90) = 90. %3D %3D
A population of bacteria begins with 200000. The population is growing according to the Malthusian growth equation given by P'(t) = 0.028 P(t), where t is in minutes. Give the solution to this differential equation. P(t): Find how long it takes for this population to double. Doubles in min. Find the population after t P(90) = 90. %3D %3D
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:A population of bacteria begins with 200000. The population is growing according to the Malthusian growth equation given by
P'(t) = 0.028P(t),
%3D
where t is in minutes. Give the solution to this differential equation.
P(t)%3D
Find how long it takes for this population to double.
Doubles in
min.
Find the population after t = 90.
P(90) =
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