A population has a mean of 60 and a standard deviation of 18. A sample of 81 observations will be taken. Find the probability that the sample mean will be larger than 66. 0.0013 O 0.3694 O 0.6306 O 0.9987

Q: A population has a mean of 200 and a standard deviation of 25. A sample of 64 observations will be…

A: We have to find out given probabiity..

Q: A population has a mean of 80 and a standard deviation of 7. A sample of 49 observations will be…

A: Given Information: Mean μ=80 Standard deviation σ=7 Sample size n=49

Q: Assume that blood pressure readings are normally distributed with a mean of 122 and a standard…

A: The following information has been given: Let X be a random variable represents the blood pressure…

Q: Assume that blood pressure readings are normally distributed with a mean of 115 and a standard…

A: # reading of blood pressure follow normal distribution with mean 115 and sd=4.8  sample of size n=32…

Q: Assume that blood pressure readings are normally distributed with a mean of 130 and a standard…

A:

Q: A population has a mean of 84 and a standard deviation of 12. A sample of 36 observations will be…

A: Mean = 84 Standard deviation = 12 Sample size = 36

Q: A population has a mean of 53 and a standard deviation of 21. A sample of 49 observations will be…

A: We have to find given probability.

Q: Find the probability that a sample of 18 has a sample mean below 32. The population mean is 24 and…

A: Central Limit Theorem for mean: If a random sample of size n is taken from a population having mean…

Q: A population has a mean of 180 and a standard deviation of 36. A sample of 81 observations will be…

A: The population mean is 180. The population standard deviation is 36. The sample size is 81. We have…

Q: A population has a mean of 300 and a standard deviation of 18. A sample of 144 observations will be…

A: Let X be a variable, for a specified sample size (n), the Z score is Z=X-μσnwhere μ=population mean…

Q: The probability that a radish seed will germinate is 0.7. A gardener plants seeds in batches of 16.…

A: Given that  Number of trials n=16 Success of probability p=0.7 q=1-p=1-0.7=0.3

Q: Assume the heights of women are normally distributed with a mean of 63.6 inches and a standard…

A: Given data Mean (µ) = 63.6 inches Standard Deviation(σ) = 2.5 inches Sample size (n)= 75 probability…

Q: The average score of all golfers for a particular course has a mean of 74 and a standard deviation…

A: Obtain the probability that average score of the 100 golfers exceeded 75. The probability that…

Q: Find the probability that a randomly selected year of rain in Sydney, Australia has a yearly…

A: Given Population mean μ=137, population standard deviations σ=69, Let X be the rain in Sydney Note:…

Q: A simple random sample of 144 observations was taken from a large population. The sample mean and…

A: sample mean is given by, x = 120.8 and sample standard deviation is given by, s = 32.46 Number of…

Q: standard

A: Given: Mean, μ=80 Standard deviation, σ=7 Sample size, n=49 To find: P (X>82) Using normal…

Q: A population has a mean of 84 and a standard deviation of 12. A sample of 36 observations be taken.…

A: Given: Population mean μ = 84 Population standard deviation σ = 12 Sample size n = 36

Q: O A. 0.8615 OB. 0.8819 O C. 0.0062 OD. 0.9938

A: Let X be the random variable from normal distribution with mean (μ) = 124, standard deviation (σ) =…

Q: The average score of all golfers for a particular course has a mean of 61 and a standard deviation…

A:

Q: A population has a mean of 80 and a standard deviation of 7. A sample of 49 observations will be…

A:

Q: The average score of all golfers for a particular course has a mean of 66 and a standard deviation…

A: Given: n= 64 The standard error can be calculated as: σX=σn=464=0.5 The z score for x = 67 can be…

Q: The average score of all golfers for a particular course has a mean of 72 and a standard deviation…

A: We want to find the probability by using standard normal distribution table

Q: A population has a mean of 180 and a standard deviation of 24. A sample of 64 observations will be…

A: Given Information: Mean μ=180 Standard deviation σ=24 Sample size n=64

Q: Assume that blood pressure readings are normally distributed with a mean of 124 and a standard…

A: Sample size [n] =64Mean =124Standard deviation =6.4

Q: A population has mean 555 and standard deviation 40. Find the mean and standard deviation of sample…

A:

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.