42A poll is taken to measure the proportion of voters who plan to vote for an ex-actor forGovernor. A 95% confidence interval is constructed, based on a sample survey of prospectivevoters. The conditions needed to construct such that an interval are present and the intervalconstructed is (0.35, 0.42). Which of the following best describes how to interpret this data? *The probability is 0.95 that about 40% of the voters will vote for the ex-actor.The sample result is most likely to be in the interval (0.35, 0.42)The probability is 0.95 that between 35% and 42% of the population will vote for the ex-actor.At least 35%, but not more than 42%, of the voters will vote for the ex-actor.

Given, 95% confidence interval isconstructed based on a sample survey. The condition is to construct…

Answered: A poll is taken to measure the…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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A survey of 300 union members in New York State reveals that 112 favor the Republican candidatefor governor. Construct the 98% confidence interval for the true population proportion of all NewYork State union members who favor the Republican candidate.
A recent survey showed that 42% of US employers were likely to require higher employee contributions for health care coverage. Suppose the survey was based on a sample of 500 companies. Find the 99% confidence interval for the proportion of all companies likely to require higher employee contributions for health care coverage. (Round to four decimal places)
In a preelection poll, a pollster finds that 442 out of 650 people polled favor Smith. Construct the 95% confidence interval for the proportion (nearest to 0.0001) of people in the whole population who favor Smith.
Suppose the cholesterol levels of 6 patients before taking a medicine (the first number) and after taking a medicine (the second number) are (242,190),(216,192),(212,215),(216,222),(212,198),(219,190), then the 90% confidence interval for the difference between the two cholesterol levels is O a. (-139.20,175.90) O b. (-88.9409,125.60) O c. (7.51,29.15) O d. (0.52,36.15) O e. None of these
Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
You recently sent out a survey to determine if the percentage of adults who use social media has changed from 56%, which was the percentage of adults who used social media five years ago. Of the 2335 people who responded to survey, 1725 stated that they currently use social media.a) Use the data from this survey to construct a 93% confidence interval estimate of the proportion of adults who use social media. Record the result below in the form of (#,#)(#,#). Round your final answer to four decimal places.
Out of a sample of 650 high school students, 321 take the bus to school every day. Construct a 99% confidence interval for the population mean of high school students that take the bus to school every day. CI = (44.34%, 54.43%) CI = (45.54%, 53.23%) CI = (46.16%, 52.61%) CI = (43.23%, 51.18%)
A student polls his school to see if students in the school district are for or against the new legislation regarding school uniforms. She surveys 600 students and finds that 480 are against the new legislation. Compute a 95% confidence interval for the true percent of students who are against the new legislation, and interpret the confidence interval.
A team of researchers aims to understand whether a sleep treatment drug has an effect on the number of hours of REM sleep. Five subjects were randomly selected and their time in REM sleep (in minutes) was measured before treatment and after treatment. The before treatment measurements are: (30, 45, 90, 60, 100). The after-treatment measurements for the same five patients are: (35, 30, 80, 70, 110). Your boss looks at the confidence interval you computed and says that it is too wide to be useful for decision making. You propose a list of changes to your methodology that may result in a narrower interval. Which option should NOT be on your list: Group of answer choices increase the confidence level recruit more subjects into the study decrease the confidence level
A state legislator wants to determine whether his voters' performance rating (00 - 100) has changed from last year to this year. The following table shows the legislator's performance from the same ten randomly selected voters for last year and this year. Use this data to find the 80% confidence interval for the true difference between the population means. Assume that the populations of voters' performance ratings are normally distributed for both this year and last year. Rating (last year) 92 46 75 62 57 75 77 74 65 65 Rating (this year) 94 56 62 66 43 84 92 72 68 81 Copy Data Step 2 of 4 : Calculate the sample standard deviation of the paired differences. Round your answer to six decimal places.
A statistics professor at a major university asked her students whether or not they wereregistered to vote. In a sample of 50 of the randomly sampled statistics students (from over1000 students), 35 said they were registered to vote. Find a 98% confidence interval and makea conclusion based upon those results.
A random sample of high school seniors were asked whether they were applying for college. The resulting confidence interval for the proportion of students applying for college is (0.65,0.69). What is the margin of error?

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