A point charge q1=-4.00nC is at the pointx=0.600 meters, y=0.800 meters, and a second pointcharge q2=+6.00nC is at the point x=0.600 meters, y=0 meters.(A) Calculate the magnitude E of the net electric field at the origin due to these two point charges.(B) What is the direction, relative to the negative x axis, of the net electric field at the origin due tothese two point charges?(C) Where would a third charge (q3-8.00 nC) need to be placed to have the net electric field at theorigin be equal to zero?

We will answer the question using formula for electric field due to a point charge. The detailed…

Answered: A point charge q1=-4.00nC is at the…

Similar questions

Two charges — q1 = 2.3 × 10-6C, q2 = 5.6 × 10-6C — are separated by a distance of d = 4.75 m. At what distance, r in meters, from the first charge is the electric field zero?
Three charges are placed at the corners of a square of side 40 cm with 1.0 μC at (0.00 m, 0.00 m), 1.0 μC at (0.00 m, 0.40 m) , and - 1.0 μC at (0.40 m, 0.00 m). Find the direction of the electric field at the fourth corner (0.40 m, 0.40 m) in degrees counter-clockwise from the +x-direction.
A finite line of charge with linear charge density ?=2.00×10−6 C/m and length L=0.742 m is located along the ?x‑axis (from x=0 to ?=?). A point charge of ?=−6.88×10−7 C is located at the point m,x0=1.00 m, y0=4.00 m. Find the electric field (magnitude and direction as measured from the +x‑axis) at the point P, which is located along the ?x‑axis at ?P=10.10 m. The Coulomb force constant is ?=1/(4?/?0)=8.99×109 (N⋅m2)/C2.
A finite line of charge with linear charge density 2 = 2.30 x 10- C/m and length L = 0.522 m is located along the x-axis (from x = 0 to x = L). A point charge of q = -7.10 × 10¬' C is located at the point xo = 1.14 m, Yo Yo = 4.00 m. Find the electric field (magnitude and direction as measured from the +x-axis) at the point P, which is located + + + L along the x-axis at xp = 10.10 m. The Coulomb force constant is k = 1/(4zle0) = 8.99 × 10° (N-m²)/C². E = N/C =
+X, to positive infinity. The line carries positive charge with a uniform linear charge density Ao. A continuous line of charge lies along the x axis, extending from x = (a) What is the magnitude of the electric field at the origin? (Use the following as necessary: 1o, xo, and ke.) 0. %3D (b) What is the direction of the electric field at the origin? O +X +y O -z
A dust particle (M=5.0x108kg) that carries charge Q=8.0x10.6℃ is placed in between two parallel plates that are equally but oppositely charged at a distance of 4.0cm from the (-) plate. The strength of this constant (uniform) electric field is E=12,500 N/C. The P.E. of Q when placed at 4.0cm from (-) plate is exactly equal to the work it can do as it is pushed to the (-) plate. is 0.004J is 400mJ Answeres a, b & c are correct. Answeres a & b are correct.
Two charges are located in the x-y plane. If q1 -3.50 nC and is located at (x = 0.00 m, y = 0.960 m), and the second charge has magnitude of q2 = 4.80 nC and is located at (x = 1.40 m, y 0.650 m), calculate the x and y components, Ex and Ey, of the electric field, É, in component form at the origin, (0, 0). The Coulomb force constant is 1/ (4reo) = 8.99 x 10° N · m²/C². -13.58 -40.45 Ex N/C Ey N/C Incorrect Incorrect II
A penny is in an external electric field of magnitude 2.5 kN/C directed perpendicular to its faces. (a) Find the charge density on each face of the penny, assuming the faces are planes. nc/m2 (b) If the radius of the penny is 1 cm, find the total charge on one face. pC
(a) Determine the electric field strength at a point 1.00 cm to the left of the middle charge shown in the figure below. (Enter the magnitude of the electric field only.) N/C(b) If a charge of −3.60 µC is placed at this point, what are the magnitude and direction of the force on it? magnitude direction
A charge q, = +5.0 x 109 C is located at the origin of an xy-coordinate system, and a charge q2 %3D = -2.0 x 10 c is located on the y-axis at y = 0.3 m. Find the components of the electric field at a point P with coordinates (0.4 m, 0.3 m).
Show that for a charged circular ring of radius a and total charge Q, the electric field anywhere inside the plane of the ring would be zero if the electric field was inversely proportional to r not r2. Your answer is partly verbal and graphical.