A plane wall of nuclear fuel with thickness L = 0.1 m, is insulated on one side at x = 0 and covered by a steel plate on the opposite side at x = L. There is no contact resistance between the steel and the fuel and open side of the steel is exposed to convection with T = 20°C and h = 400 W/m²/K. The steel plate has thickness b = .03 m and thermal conductivity kst = 15.1 W/m/K. The nuclear fuel has thermal conductivity kf= 1.4 W/m/K and provides a uniform volumetric heat generation of q=150 kW/m³. For steady-state conditions, neatly sketch the temperature profile shape and determine the maximum temperature in the wall by: a) Use resistance analogy to determine the temperature at the fuel-steel interface TL in terms of constant parameters q, L, b, kst, T, h and/or any other necessary parameters. b) Develop an expression for the steady-state temperature distribution within the fuel in terms of constant parameters q., L, kf, T₁ and/or any other necessary parameters. Hint: Consider an isothermal boundary condition T(x=L) TL found in part a). c) For the given parameter values, calculate the maximum temperature in the wall. d) Neatly plot the temperature distribution in the wall. Nuclear fuel The general heat equation is provided for reference. ƏT pc Ət · = kV²T+q qo L Steel ↑↑↑ To, h

Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
icon
Related questions
Question
A plane wall of nuclear fuel with thickness L = 0.1 m, is insulated on one side at x = 0 and covered by
a steel plate on the opposite side at x = L. There is no contact resistance between the steel and the
fuel and open side of the steel is exposed to convection with T = 20°C and h = 400 W/m²/K. The
steel plate has thickness b = .03 m and thermal conductivity kst = 15.1 W/m/K. The nuclear fuel has
thermal conductivity kf= 1.4 W/m/K and provides a uniform volumetric heat generation of
q=150 kW/m³. For steady-state conditions, neatly sketch the temperature profile shape and
determine the maximum temperature in the wall by:
a) Use resistance analogy to determine the temperature at the fuel-steel interface TL in terms of
constant parameters à, L, b, kst, T, h and/or any other necessary parameters.
b) Develop an expression for the steady-state temperature distribution within the fuel in terms
of constant parameters q., L, kf, T₁ and/or any other necessary parameters.
Hint: Consider an isothermal boundary condition T(x =L) = T₁ found in part a).
For the given parameter values, calculate the maximum temperature in the wall.
d) Neatly plot the temperature distribution in the wall.
c)
Nuclear fuel
The general heat equation is provided for reference.
ƏT
pc. ==
Ət
= kV²T + q
Steel
↑↑↑
HE
b
To, h
Transcribed Image Text:A plane wall of nuclear fuel with thickness L = 0.1 m, is insulated on one side at x = 0 and covered by a steel plate on the opposite side at x = L. There is no contact resistance between the steel and the fuel and open side of the steel is exposed to convection with T = 20°C and h = 400 W/m²/K. The steel plate has thickness b = .03 m and thermal conductivity kst = 15.1 W/m/K. The nuclear fuel has thermal conductivity kf= 1.4 W/m/K and provides a uniform volumetric heat generation of q=150 kW/m³. For steady-state conditions, neatly sketch the temperature profile shape and determine the maximum temperature in the wall by: a) Use resistance analogy to determine the temperature at the fuel-steel interface TL in terms of constant parameters à, L, b, kst, T, h and/or any other necessary parameters. b) Develop an expression for the steady-state temperature distribution within the fuel in terms of constant parameters q., L, kf, T₁ and/or any other necessary parameters. Hint: Consider an isothermal boundary condition T(x =L) = T₁ found in part a). For the given parameter values, calculate the maximum temperature in the wall. d) Neatly plot the temperature distribution in the wall. c) Nuclear fuel The general heat equation is provided for reference. ƏT pc. == Ət = kV²T + q Steel ↑↑↑ HE b To, h
Expert Solution
steps

Step by step

Solved in 3 steps with 8 images

Blurred answer
Knowledge Booster
Conduction
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, mechanical-engineering and related others by exploring similar questions and additional content below.
Similar questions
Recommended textbooks for you
Elements Of Electromagnetics
Elements Of Electromagnetics
Mechanical Engineering
ISBN:
9780190698614
Author:
Sadiku, Matthew N. O.
Publisher:
Oxford University Press
Mechanics of Materials (10th Edition)
Mechanics of Materials (10th Edition)
Mechanical Engineering
ISBN:
9780134319650
Author:
Russell C. Hibbeler
Publisher:
PEARSON
Thermodynamics: An Engineering Approach
Thermodynamics: An Engineering Approach
Mechanical Engineering
ISBN:
9781259822674
Author:
Yunus A. Cengel Dr., Michael A. Boles
Publisher:
McGraw-Hill Education
Control Systems Engineering
Control Systems Engineering
Mechanical Engineering
ISBN:
9781118170519
Author:
Norman S. Nise
Publisher:
WILEY
Mechanics of Materials (MindTap Course List)
Mechanics of Materials (MindTap Course List)
Mechanical Engineering
ISBN:
9781337093347
Author:
Barry J. Goodno, James M. Gere
Publisher:
Cengage Learning
Engineering Mechanics: Statics
Engineering Mechanics: Statics
Mechanical Engineering
ISBN:
9781118807330
Author:
James L. Meriam, L. G. Kraige, J. N. Bolton
Publisher:
WILEY