A pith ball of mass 0.20 grams and charge -3.0 nC hangs from an insulating thread and is repelled by the charged metallic sphere of a Van de Graaff generator. It is noted that the thread is tilted by 17 deg when the pith ball hangs at rest 0.30 m from the center of the sphere. Determine the electric field at that position.
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- An electron has an initial speed of 5.21 x 106 m/s in a uniform 4.69 x 105 N/C strength electric field. The field accelerates the electron in the direction opposite to its initial velocity. (a) What is the direction of the electric field? opposite direction to the electron's initial velocity same direction as the electron's initial velocity O not enough information to decide (b) How far does the electron travel before coming to rest? m (c) How long does it take the electron to come to rest? (d) What is the electron's speed when it returns to its starting point? m/sA simple and common technique for accelerating electrons is shown in the figure below, where a uniform electric field is created between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to continue moving. (a) Calculate the acceleration of the electron if the field strength is 3.45 x 104 N/C. m/s² (b) Why will the electron not be pulled back to the positive plate once it moves through the hole? O The force of gravity is too strong. O There is no field outside the plates. O The other side of the positive plate also has a negative charge.A proton is shot in a region with a velocity 2×106 m/s along positive x- .direction An electric field É = -(120 kN/C)í exists in the region. (1kN = 1000 N) .mass of proton = 1.67x1027 kg %3D How far does the proton travel along the x-axis before reaching its turning ?point
- What is the magnitude of an electric field at a point that is 4.24 meters away from a 1.95C charge?Problem 12: A simple and common technique for accelerating electrons is shown in the figure, which depicts a uniform electric field between two plates. Electrons are released, usually from a hot filament, near the negative plate, and there is a small hole in the positive plate that allows the electrons to pass through. E = 2.4 × 104 N/C Calculate the horizontal component of the electron's acceleration if the field strength is 2.4 × 104 N/C. Express your answer in meters per second squared, and assume the electric field is pointing in the negative x-direction as shown in the figure.#2: A 0.050-kg cart has a spherical dome that is charged to +1.0 x 10- C. The cart is at the top of a 2.0-m-long inclined plane that makes a 30° angle with the horizontal. The cart and the plane are placed in an upward-pointing vertical uniform 4000-N/C E field. How long will it take the cart to reach the bottom of the plane? What assumptions did you make?
- A 3.66 nC charge is placed at the origin (x = 0.0, y = 0.0). What is the y-component of the electric field at the location (x = 6.0 m, y = 8.0 m) due to the charge at the origin? Please enter a numerical answer below. Accepted formats are numbers or "e" based scientific notation e.g. 0.23, -2, 1e6, 5.23e-8 Enter answer here N/CLong highway tunnels must have air cleaners to remove dust and soot coming from passing cars and trucks. In one type, known as an electrostatic precipitator, air passes between two oppositely charged metal plates, as shown. The large electric field between the plates ionizes dust and soot particles, which then feel a force due to the field. This force causes the charged particles to move toward and stick to one or the other plate, removing them from the air. A typical unit has dimensions and charges asshown. What is the electric field between the plates?