A pitcher throws 0.90 kg ball of clay at 5.0 kg block of wood the clay sticks to the wood on impact and their joint velocity afterwords is 2.1 m/s. What was the original speed of the clay in m/s?

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Chapter1: Units, Trigonometry. And Vectors
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A pitcher throws 0.90 kg ball of clay at 5.0 kg block of wood the clay sticks to the wood on impact and their joint velocity afterwords is 2.1 m/s. What was the original speed of the clay in m/s?
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Step 1

Let original speed of the clay ball be u m/s .

Than initial momentum = momentum of wood + momentum of clay ball = 0.90u+0 ( as speed of the block us zero initially so its initial momentum= 0.

Final momentum of clay = 0.90×2.1 

Final momentum of wooden block = 0.50×2.1 

Total final momentum= (0.90+0.50)×2.1 = 1.4×2.1 = 3.04 kg m/s. 

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