**Problem Statement**A pipe has an outer diameter of 26 mm and an inner diameter of 19 mm. What is the polar moment of inertia "J" for the shaft in mm\(^4\)?**Solution Input Area**Type your answer...---This problem involves calculating the polar moment of inertia, an important property in mechanical engineering and physics, particularly relevant in analyzing torsional stress in cylindrical shafts. The polar moment of inertia, denoted by "J", is crucial for predicting an object's ability to resist torsion. In this problem, the given values are the outer and inner diameters of a pipe. The solution will require the use of the formula for the polar moment of inertia for a hollow cylinder:\[J = \frac{\pi}{32} (d_o^4 - d_i^4)\]where \(d_o\) is the outer diameter and \(d_i\) is the inner diameter.

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A pipe has an outer diameter of 26 mm and an inner diameter of 19 mm. What is the polar moment of inertia "J" for the shaft in mm^4? Type your answer...

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Material Properties

Construction in civil engineering demands high strength, durability, and longevity. These targets can be achieved by better design and analysis, along with the correct choice of materials. Different materials have different properties and hence, they respond and performs differently under the various condition of external loadings. It is therefore a critical task of an engineer to select the right material based on the property that the material is supposed to function in real-time. When speaking about the property, there are different categories of material properties like chemical property, physical property, mechanical property, electrical property, magnetic property, thermal property, etc. These material properties form the basis of material selection in various applications.

Question

**Problem Statement**

A pipe has an outer diameter of 26 mm and an inner diameter of 19 mm. What is the polar moment of inertia "J" for the shaft in mm\(^4\)?

**Solution Input Area**

Type your answer...

---

This problem involves calculating the polar moment of inertia, an important property in mechanical engineering and physics, particularly relevant in analyzing torsional stress in cylindrical shafts. The polar moment of inertia, denoted by "J", is crucial for predicting an object's ability to resist torsion. In this problem, the given values are the outer and inner diameters of a pipe. The solution will require the use of the formula for the polar moment of inertia for a hollow cylinder:

\[
J = \frac{\pi}{32} (d_o^4 - d_i^4)
\]

where \(d_o\) is the outer diameter and \(d_i\) is the inner diameter.

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