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Problem 6.059 The pipe shown has a 180°vertical bend in it. The diameter D is 1.25 ft, and the pressure at the center of the upper pipe is 15 psig. If the flow in the bend is 40 cfs, what are the (a) x-component and (b) y-component of external force required to hold the bend in place against the action of the water? The bend weighs 200 lbf, and the volume of the bend is 3 ft³. Assume the Bernoulll equation applies. (p = 62.4 lbm/ft²) (a) Fx = (b) Fy = Ibf Ibf A D

Problem 6.059 The pipe shown has a 180°vertical bend in it. The diameter D is 1.25 ft, and the pressure at the center of the upper pipe is 15 psig. If the flow in the bend is 40 cfs, what are the (a) x-component and (b) y-component of external force required to hold the bend in place against the action of the water? The bend weighs 200 lbf, and the volume of the bend is 3 ft³. Assume the Bernoulll equation applies. (p = 62.4 lbm/ft²) (a) Fx = (b) Fy = Ibf Ibf A D

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Problem 6.059 The pipe shown has a 180°vertical bend in it. The diameter D is 1.25 ft, and the pressure at the center of the upper pipe is 15 psig. If the flow in the bend is 40 cfs, what are the (a) x-component and (b) y-component of external force required to hold the bend in place against the action of the water? The bend weighs 200 lbf, and the volume of the bend is 3 ft³. Assume the Bernoulll equation applies. (p = 62.4 lbm/ft²) (a) Fx = (b) Fy = Ibf Ibf A D
Transcribed Image Text:Problem 6.059 The pipe shown has a 180°vertical bend in it. The diameter D is 1.25 ft, and the pressure at the center of the upper pipe is 15 psig. If the flow in the bend is 40 cfs, what are the (a) x-component and (b) y-component of external force required to hold the bend in place against the action of the water? The bend weighs 200 lbf, and the volume of the bend is 3 ft³. Assume the Bernoulll equation applies. (p = 62.4 lbm/ft²) (a) Fx = (b) Fy = Ibf Ibf A D
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