A ping pong ball is drawn at random from an urn consisting of balls numbered 4 through 9. A player wins $1.5 if the number on the ball is odd and loses $1 if the number is even. Let x be the amount of money a player will win/lose when playing this game, where x is negative when the player loses money. (a) Construct the probability distribution table for this game. Round your answers to two decimal places. Probability P(x) Outcome

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**Problem Statement:**

A ping pong ball is drawn at random from an urn consisting of balls numbered 4 through 9. A player wins $1.5 if the number on the ball is odd and loses $1 if the number is even.

Let \( x \) be the amount of money a player will win/lose when playing this game, where \( x \) is negative when the player loses money.

**Tasks:**

(a) Construct the probability distribution table for this game. Round your answers to two decimal places.

| Outcome | \( x \) | Probability P(x) |
|---------|--------|-------------------|
|         |        |                   |
|         |        |                   |
|         |        |                   |
|         |        |                   |
|         |        |                   |
|         |        |                   |

(b) What is the expected value of the player's winnings? Round to the nearest hundredth.

\[ E(x) = \]

(c) Interpret the meaning of the expected value in the context of this problem.

\[ \text{Interpretation:} \]

**Explanation of the Diagram:**

There are no graphs or diagrams included in the provided image. The image contains a problem statement involving the calculation of probabilities and an expected value, a layout for constructing a probability distribution table, and spaces for calculating and interpreting the expected value.

---

### Explanation:

1. **Probability Distribution Table:**

   - **Possible Outcomes:** The outcomes depend on whether the ball drawn has an even or odd number.
   - **Amount Won/Lost (x):** Player wins $1.5 for odd numbers (5, 7, 9) and loses $1 for even numbers (4, 6, 8).
   - **Probability P(x):** Since the numbers 4 through 9 are equally likely, each has a probability of \(\frac{1}{6}\).

2. **Expected Value Calculation:**
  
   The expected value \( E(x) \) is calculated by multiplying each outcome \( x \) by its corresponding probability P(x) and summing these products.

3. **Interpretation:**

   The expected value gives the average amount a player can expect to win or lose per game over a large number of trials. 

### Filling in the Table:

   - For the numbers 5, 7, 9: Winners
     - \( x = 1.5 \)
     - Probability
Transcribed Image Text:**Problem Statement:** A ping pong ball is drawn at random from an urn consisting of balls numbered 4 through 9. A player wins $1.5 if the number on the ball is odd and loses $1 if the number is even. Let \( x \) be the amount of money a player will win/lose when playing this game, where \( x \) is negative when the player loses money. **Tasks:** (a) Construct the probability distribution table for this game. Round your answers to two decimal places. | Outcome | \( x \) | Probability P(x) | |---------|--------|-------------------| | | | | | | | | | | | | | | | | | | | | | | | | (b) What is the expected value of the player's winnings? Round to the nearest hundredth. \[ E(x) = \] (c) Interpret the meaning of the expected value in the context of this problem. \[ \text{Interpretation:} \] **Explanation of the Diagram:** There are no graphs or diagrams included in the provided image. The image contains a problem statement involving the calculation of probabilities and an expected value, a layout for constructing a probability distribution table, and spaces for calculating and interpreting the expected value. --- ### Explanation: 1. **Probability Distribution Table:** - **Possible Outcomes:** The outcomes depend on whether the ball drawn has an even or odd number. - **Amount Won/Lost (x):** Player wins $1.5 for odd numbers (5, 7, 9) and loses $1 for even numbers (4, 6, 8). - **Probability P(x):** Since the numbers 4 through 9 are equally likely, each has a probability of \(\frac{1}{6}\). 2. **Expected Value Calculation:** The expected value \( E(x) \) is calculated by multiplying each outcome \( x \) by its corresponding probability P(x) and summing these products. 3. **Interpretation:** The expected value gives the average amount a player can expect to win or lose per game over a large number of trials. ### Filling in the Table: - For the numbers 5, 7, 9: Winners - \( x = 1.5 \) - Probability
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