A piece of aluminum foil is 0.0150 cm thick. Calculate the thickness of the aluminum foil in terms of the number of aluminum atoms. Assume that the aluminum atoms are spheres with a radius of 143 pm, and that they are stacked one on top of another.
A piece of aluminum foil is 0.0150 cm thick. Calculate the thickness of the aluminum foil in terms of the number of aluminum atoms. Assume that the aluminum atoms are spheres with a radius of 143 pm, and that they are stacked one on top of another.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Step 1
Thickness of the aluminum foil = 0.0150 cm
= 0.0150 *10-2 m
Radius of the alluminium atom = 143 pm
Diameter of the alluminium atom = 2*143 pm
= 286 pm
= 286* 10-12 m
We have to calculate the thickness of the aluminum foil in terms of the number of aluminum atoms.
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