Answered: A physics student constantly swings a…

Similar questions

We used an experimental setup like the one shown below. The length of the string between the string vibrator and the pulley is L = 2.00 m. The mass per unit length or linear density of the string is μ = 0.0005 kg/m. The string vibrator can oscillate at any frequency. The hanging mass is 511 g. Frictionless pulley String vibrator μl= dm dx The wavelength of the fifth mode (n = 5) is m. The frequency of the fifth mode (n = 5) is Hz. The tension in the string is close to When the mode of vibration is increased to n = 10, the wave speed of the string will → 2 The wave speed on the string is m/s. N. constant Drag answer here Drag answer here Drag answer here Drag answer here Drag answer here m Hanging mass 500 125 remain the same 0.8 100 2.0 increase
A wave has a wavelength of 30 cm. What is the phase difference between two points on this wave that are 45 cm apart? π/4 rad π/3 rad π/2 rad 2π/3 rad π rad
A 1m long string is pinned at both ends. The string is plucked, and a standing wave is created. The wave number is ? = 4? rad/m.a) Calculate the wavelength of the wave.b) If there are 5 nodes in the string, find their positions.Answers: • 0.5 m• Xn = {0, 0.25, 0.5, 0.75, 1}
In the arrangement shown in the figure below, an object of mass m = 2.0 kg hangs from a cord around a light pulley. The length of the cord between point P and the pulley is L= 2.0 m. (Ignore the mass of the vertical section of the cord.) Vibrator P н X kg/m L m ii (a) When the vibrator is set to a frequency of 130 Hz, a standing wave with six loops is formed. What must be the linear mass density of the cord? 6895 (b) How many loops (if any) will result if m is changed to 4.50 kg? (Enter 0 if no loops form.) X loops 0 (c) How many loops (if any) will result if m is changed to 14 kg? (Enter 0 if no loops form.) 0 loops
Chapter 35, Problem 029 Two waves of the same frequency have amplitudes 0.843 and 2.41. They interfere at a point where their phase difference is 79.0°. What is the resultant amplitude? Number Units Use correct number of significant digits; the tolerance is +/-2%

	antinodes = 20 cm, nodes = 0 cm, wavelength = 1.5 λ
	antinodes = 20 cm, nodes = 0 cm, wavelength = 1.75 λ
	antinodes = 40 cm, nodes = 0 cm, wavelength = 1.5