A physics professor jumps on a trampoline, jumping higher and higher with every bounce. How is this possible, if energy conservation is not being violated? Be sure to note for which object(s) energy is conserved during this process.
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- Solution to HW problem with all work and explanation, please.Releasing some frustration at the end of the semester, you throw your physics book (mass of 2.7 kg) off of a 25 m tall building. You throw your book so that it has a speed of 6 m/s right after you let go. What is the kinetic energy of your book after you let go? (in J) 16.2 130. 0 48.6 662 How how fast is your textbook moving right before it lands? For now, ignore friction. (in m/s) 28.1 22.9 21.3 16.7(8c7p19) A cord is used to vertically lower an initially stationary block of mass M = 45 ką at a constant downward acceleration of q/7. When the block has fallen a distance d = 4.5 m, find the work done by the cord's force on the block. Submit Answer Tries 0/5 Find the work done by the weight of the block. Submit Answer Tries 0/5 Find the kinetic energy of the block. Submit Answer Tries 0/5 Find the speed of the block. Submit Answer Tries 0/5
- = 13 kg, and m3 20 kg, respectively, are attached by strings over frictionless pulleys as indicated in the figure below. The horizontal surface 3.4 kg, m2 %3D Three objects with masses m, exerts a force of friction of 30 N on m,. If the system is released from rest, use energy concepts to find the speed of m, after it moves down 4.0 m. m/s m2 m1 m3Can the work done by Friction be zero? In a case where static friction exists, the object does not move and the change in kinetic energy is also zero? W = Fd = ?KE = 0? What did I do wrong?⦁ Envision yourself doing a jumping jack. Imagine you assume a standing X position, with your arms above your shoulders in a wide V and legs apart in an inverted V. When you hold that position, you are demonstrating ______ energy. When you do the jumping jack from the previous position you are converting that energy into _____ energy. ,
- The driver of a 760.0 kg car decides to double the speed from 21.1 m/s to 42.2 m/s. What effect would this have on the amount of work required to stop the car, that is, on the kinetic energy of the car? KE x 105 J KE = × 105 J (select) v times as much work must be done to stop the car.to search 82 W You observe a car of mass 500 kg, moving at speed 5 m/s, collide with a 100 kg trailer that was at rest before the collision. When does the car do work on the trailer? Choose all that are correct. # 3 before the collision during the collision after the collision none of these * E Previous Page D S 4 O Et R F % Shee 5 Next Page V T G B NO 19 Y & H 99+ N J X 7 Page 2 of 5 ME 64°FDETAILS SERPSE10 7.8.P.035.MI. (a) the work done by this force on the particle 1 A single conservative force acts on a 5.30-kg particle within a system due to its interaction with the rest of the system. The equation F, 2x + 4 describes the force, where F, is in newtons and is n meters. As the particle moves along the x axis from x 1.02 m tox-6.20 m, calculate the following (b) the change in the potential energy of the system (c) the kinetic energy the particle has at x 6.20 m if its speed is 3.00 m/s at x 1.02 m 3 Need Help? MY NOTES Pa ASK YOUR TEACHER PRACTICE ANOTHER