A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.395 Hz. The pendulum has a mass of 2.10 kg, and the pivot is located 0.370 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. Pivot CM d sin 0
Simple harmonic motion
Simple harmonic motion is a type of periodic motion in which an object undergoes oscillatory motion. The restoring force exerted by the object exhibiting SHM is proportional to the displacement from the equilibrium position. The force is directed towards the mean position. We see many examples of SHM around us, common ones are the motion of a pendulum, spring and vibration of strings in musical instruments, and so on.
Simple Pendulum
A simple pendulum comprises a heavy mass (called bob) attached to one end of the weightless and flexible string.
Oscillation
In Physics, oscillation means a repetitive motion that happens in a variation with respect to time. There is usually a central value, where the object would be at rest. Additionally, there are two or more positions between which the repetitive motion takes place. In mathematics, oscillations can also be described as vibrations. The most common examples of oscillation that is seen in daily lives include the alternating current (AC) or the motion of a moving pendulum.
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Tutorial Exercise
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of
0.395 Hz. The pendulum has a mass of 2.10 kg, and the pivot is located 0.370 m from the center of mass.
Determine the moment of inertia of the pendulum about the pivot point.
Pivot
CM
d sin 0
Part 1 of 3 - Conceptualize
We expect a moment of inertia on the order of 1 kg · m/s².
Part 2 of 3 - Categorize
The equations used to describe the physical pendulum will lead us directly to an answer.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fb846e3c1-ca19-4e44-9164-32f2e9be6f72%2F87de5b2b-e0ba-4f6f-972f-ac83eb9bfb02%2Fog24i2c_processed.png&w=3840&q=75)
![Part 2 of 3 - Categorize
The equations used to describe the physical pendulum will lead us directly to an answer.
Part 3 of 3 - Analyze
We are given f = 0.395 Hz, d = 0.370 m, and m = 2.10 kg. We have the following equation for the period.
I
T = 2n
mgd
This gives
4x²I
mgd
and, solving for the moment of inertia, we have the following.
Tmgd
I =
4x2
-(주)
1\2 mgd
kg) (9.80 m/s?
)(
Hz
kg · m2
Submit
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