A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.395 Hz. The pendulum has a mass of 2.10 kg, and the pivot is located 0.370 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. Pivot CM d sin 0

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Tutorial Exercise
A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of
0.395 Hz. The pendulum has a mass of 2.10 kg, and the pivot is located 0.370 m from the center of mass.
Determine the moment of inertia of the pendulum about the pivot point.
Pivot
CM
d sin 0
Part 1 of 3 - Conceptualize
We expect a moment of inertia on the order of 1 kg · m/s².
Part 2 of 3 - Categorize
The equations used to describe the physical pendulum will lead us directly to an answer.
Transcribed Image Text:This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive any points for the skipped part, and you will not be able to come back to the skipped part. Tutorial Exercise A physical pendulum in the form of a planar object moves in simple harmonic motion with a frequency of 0.395 Hz. The pendulum has a mass of 2.10 kg, and the pivot is located 0.370 m from the center of mass. Determine the moment of inertia of the pendulum about the pivot point. Pivot CM d sin 0 Part 1 of 3 - Conceptualize We expect a moment of inertia on the order of 1 kg · m/s². Part 2 of 3 - Categorize The equations used to describe the physical pendulum will lead us directly to an answer.
Part 2 of 3 - Categorize
The equations used to describe the physical pendulum will lead us directly to an answer.
Part 3 of 3 - Analyze
We are given f = 0.395 Hz, d = 0.370 m, and m = 2.10 kg. We have the following equation for the period.
I
T = 2n
mgd
This gives
4x²I
mgd
and, solving for the moment of inertia, we have the following.
Tmgd
I =
4x2
-(주)
1\2 mgd
kg) (9.80 m/s?
)(
Hz
kg · m2
Submit
Skip (you cannot come back).
Transcribed Image Text:Part 2 of 3 - Categorize The equations used to describe the physical pendulum will lead us directly to an answer. Part 3 of 3 - Analyze We are given f = 0.395 Hz, d = 0.370 m, and m = 2.10 kg. We have the following equation for the period. I T = 2n mgd This gives 4x²I mgd and, solving for the moment of inertia, we have the following. Tmgd I = 4x2 -(주) 1\2 mgd kg) (9.80 m/s? )( Hz kg · m2 Submit Skip (you cannot come back).
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