My library > MAT 240: Applied Statistics home >EzyBooks catalog2: Hypothesis test for the difference between two population proportionsJump to level 1A pharmaceutical company is trying to determine if a new drug is more effective than the current standard drug.The company tracks random samples of patients on each drug and calculates the proportion that see animprovement in symptoms after six months. The results of the data collected are shown below.What are the population parameters?PickOld drugSuccesses419 Successes261What is the level of significance? Ex: 0.12Observations500 Observations300p-hat_10.838 p-hat_20.870What is the null hypothesis Ho?PickConfidence Level99%Z-scoreWhat is the alternative hypothesis Ha? Pick1.227p-value0.1094Should Ho be rejected or does Ho fail to be rejected? PickWhat conclusion can be drawn from the data?Pickevidence exists to support the claim that more patients on the new drug see improvements insymptoms than patients on the current drug.2NextWDI7CheckNew drugBILL)))? HelpMAINE11

Given that: Old drug New drug Successes 419 Successes 261 Observations 500 Observations 300…

Answered: A pharmaceutical company is trying to…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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1. Show a One-Way ANOVA using the dataset found in the given excel (Sheet name: Smoking). Copy the result of the statistics and provide an interpretation of it. Description of Data: A research was conducted to quantify the effect of cigarette smoking on standard measures of lung function in patients with idiopathic pulmonary fibrosis. 2. Show a Two-Way ANOVA using the dataset found in the given excel (Sheet name: Trauma). Copy the result of the statistics and provide an interpretation of it. Description of Data: The research compares different combinations of four types of psychiatric treatment (A, B, C, and D) and six physical therapy programs (I, II, III, IV, V, and VI). •(NOTE: This is my one last remaining question. So, please answer the two given situations.)
Which uses a group of people with different exposures and follows them over time? Cohort Cross-sectional Quasi-experimental Case-Control
When a t-test is used to compare pre- and post-treatment data. What does the t-test reveal about the difference between baseline and treatment?
Please answer these questions thanks
Individual actions can play a large role in the overall health of our planet. A researcher interested in evaluating environment friendly behaviors evaluated how often people recycle (per month) based on whether they have an overall optimistic or an overall pessimistic attitude toward eco-friendly behaviors. The results from this hypothetical study are given in the table. Test whether or not recycling behaviors differed between groups using a .05 level of significance. State the value of the test statistics and the decision to retain or reject the null hypothesis. Compute effect size using eta- squared (n^2). Pessimistic Optimistic 3 4 0 9 4 6 2 8 1 9 6 5 3 6 5 8 0 6 5 7
Find the 5 number summary for the data shown 5.4 7 9.2 13.8 19.9 21.9 23.3 26.1 5 number summary: Use the Locator/Percentile method described in your book, not your calculator. Submit Question E
Choose the appropriate statistical test. When computing, be sure to round each answer as indicated. A dentist wonders if depression affects ratings of tooth pain. In the general population, using a scale of 1-10 with higher values indicating more pain, the average pain rating for patients with toothaches is 6.8. A sample of 30 patients that show high levels of depression have an average pain rating of 7.1 (variance 0.8). What should the dentist determine? 1. Calculate the estimated standard error. (round to 3 decimals). [st.error] 2. What is thet-obtained? (round to 3 decimals). 3. What is the t-cv? (exact value) 4. What is your conclusion? Only type "Reject" or Retain"
A doctor in Oklahoma City wants to know whether the average life span for heart disease patients at four hospitals in the city differ. The data below represents the life span, in years, of heart disease patients from each hospital. Perform an ANOVA test with a 10% level of significance to test whether the average life span of heart disease patients in Oklahoma City differs depending on the hospital that treats them Life Span of Patients Treated at Hospital 1: 8.1, 1.2, 7, 11.5, 21, 2, 15.3, 19.2, 10.5, 15.4, 12.7, 15.3, 12.1, 7.5, 11.4, 16.4, 26.7, 14.6, 1.5, 16.3, 12.6, 0.8, 18.2, 4.2, 9.6, 21, 16.3, 2.7 Life Span of Patients Treated at Hospital 2: 17.6, 11.6, 16.8, 5.2, 6.7, 3.2, 13.8, 12.5, 0.9, 6, 14.3, 1.8, 14.8, 10, 5.8, 15.2, 10, 3.7, 11.4, 21.6, 12.9, 0.5, 9.2, 13.9, 10.9 ▼ Part 1 of 4 Life Span of Patients Treated at Hospital 3: 8.5, 2.3, 11, 7.4, 14.8, 5.8, 11, 3.4, 10.9, 1.1, 5.9, 21.6, 12.5, 0.1, 15.5, 15.4, 0.8, 7.7, 5.6, 12, 7.1 Life Span of Patients Treated at Hospital…
The number of hours per week that the television is turned on is determined for each family in a sample. The mean of the data is 31 hours and the median is 27.2hours. Twenty-four of the families in the sample turned on the television for 16 hours or less for the week. The 8th percentile of the data is 16 hours. Based on the given information, determine if the following statement is true or false. The first quartile is less than 16 hours.
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