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A pharmaceutical company is about to launch a new manufacturing process in addition to the existing one. The quality control manager believes that the new method results in a different variation in the weights of the capsules. To verify the claim, the samples from each production line were obtained and the results are below (in mg): Production Line 1: 100.7 104.7 101.9 101.6 98.9 101 100.3 101 98.8 99.4 (Note: The average and the standard deviation of the data are respectively 100.83 mg and 1.731 mg.) Production Line 2: 101.6 100.4 99.1 100 99 97.5 98.6 99.5 102 97.6 99.9 102.5 100.4 98.6 99.1 100.8 99.3 (Note: The average and the standard deviation of the data are respectively 99.76 mg and 1.416 mg.) Use a 1% significance level to test the claim that the standard deviation of the capsule weights in the production line 1 is greater than the standard deviation of the capsule weights in the production line 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Assumptions: (select everything that applies) Population standard deviation are unknown Paired samples Sample sizes are both greater than 30 The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal Independent samples Population standard deviations are known

A pharmaceutical company is about to launch a new manufacturing process in addition to the existing one. The quality control manager believes that the new method results in a different variation in the weights of the capsules. To verify the claim, the samples from each production line were obtained and the results are below (in mg): Production Line 1: 100.7 104.7 101.9 101.6 98.9 101 100.3 101 98.8 99.4 (Note: The average and the standard deviation of the data are respectively 100.83 mg and 1.731 mg.) Production Line 2: 101.6 100.4 99.1 100 99 97.5 98.6 99.5 102 97.6 99.9 102.5 100.4 98.6 99.1 100.8 99.3 (Note: The average and the standard deviation of the data are respectively 99.76 mg and 1.416 mg.) Use a 1% significance level to test the claim that the standard deviation of the capsule weights in the production line 1 is greater than the standard deviation of the capsule weights in the production line 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Assumptions: (select everything that applies) Population standard deviation are unknown Paired samples Sample sizes are both greater than 30 The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal Independent samples Population standard deviations are known

MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A pharmaceutical company is about to launch a new manufacturing process in addition to the existing one. The quality control manager believes that the new method results in a different variation in the weights of the capsules. To verify the claim, the samples from each production line were obtained and the results are below (in mg): Production Line 1: 100.7 104.7 101.9 101.6 98.9 101 98.8 99.4 101 100.3 (Note: The average and the standard deviation of the data are respectively 100.83 mg and 1.731 mg.) Production Line 2: 101.6 100.4 99.1 99 98.6 100 97.5 99.5 102 97.6 99.9 102.5 100.4 98.6 99.1 100.8 99.3 Part 1 of 5 (Note: The average and the standard deviation of the data are respectively 99.76 mg and 1.416 mg.) Use a 1% significance level to test the claim that the standard deviation of the capsule weights in the production line 1 is greater than the standard deviation of the capsule weights in the production line 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Assumptions: (select everything that applies) Population standard deviation are unknown Paired samples Sample sizes are both greater than 30 The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal Independent samples Population standard deviations are known
Transcribed Image Text:A pharmaceutical company is about to launch a new manufacturing process in addition to the existing one. The quality control manager believes that the new method results in a different variation in the weights of the capsules. To verify the claim, the samples from each production line were obtained and the results are below (in mg): Production Line 1: 100.7 104.7 101.9 101.6 98.9 101 98.8 99.4 101 100.3 (Note: The average and the standard deviation of the data are respectively 100.83 mg and 1.731 mg.) Production Line 2: 101.6 100.4 99.1 99 98.6 100 97.5 99.5 102 97.6 99.9 102.5 100.4 98.6 99.1 100.8 99.3 Part 1 of 5 (Note: The average and the standard deviation of the data are respectively 99.76 mg and 1.416 mg.) Use a 1% significance level to test the claim that the standard deviation of the capsule weights in the production line 1 is greater than the standard deviation of the capsule weights in the production line 2. If normality plots are not provided assume that the samples are from normal populations. Procedure: Select an answer Assumptions: (select everything that applies) Population standard deviation are unknown Paired samples Sample sizes are both greater than 30 The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal Independent samples Population standard deviations are known
Procedure: Select an answer Select an answer Assumption Two proportions Z Hypothesis Test Two means T (pooled) Hypothesis Test Popu Two means T (non-pooled) Hypothesis Test Paire Two paired means T Hypothesis Test Two variances F Hypothesis Test Samp Two means Z Hypothesis Test The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal O Independent samples Population standard deviations are known
Transcribed Image Text:Procedure: Select an answer Select an answer Assumption Two proportions Z Hypothesis Test Two means T (pooled) Hypothesis Test Popu Two means T (non-pooled) Hypothesis Test Paire Two paired means T Hypothesis Test Two variances F Hypothesis Test Samp Two means Z Hypothesis Test The number of positive and negative responses are both greater than 10 for both samples Simple random samples Normal populations Population standard deviation are unknown but assumed equal O Independent samples Population standard deviations are known
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Step 1. Hypotheses Set-Up: Ho: Select an answer Ha: Select an answer Step 2. The significance level = Provide the critical value(s) for the Rejection Region: left CV is and right CV is Step 5. Decision: where Select an answer the Select an answer units are Select an answer Step 3. Compute the value of the test statistic: Select an answer decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Is the test statistic in the rejection region? ? Conclusion: Select an answer . and the test is Select an answer Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Step 6. Interpretation: 1% At % significance level we [Select an answer hypothesis in favor of the alternative hypothesis. E and the (Round the answer to 3 PVA Compute the P-value of the test statistic: P-value is PVA Is the P-value less than the significance level? have sufficient evidence to reject the null 11:19 AM 7/11/2020
Transcribed Image Text:Step 1. Hypotheses Set-Up: Ho: Select an answer Ha: Select an answer Step 2. The significance level = Provide the critical value(s) for the Rejection Region: left CV is and right CV is Step 5. Decision: where Select an answer the Select an answer units are Select an answer Step 3. Compute the value of the test statistic: Select an answer decimal places) Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Is the test statistic in the rejection region? ? Conclusion: Select an answer . and the test is Select an answer Step 4. Testing Procedure: (Round the answers to 3 decimal places) CVA Step 6. Interpretation: 1% At % significance level we [Select an answer hypothesis in favor of the alternative hypothesis. E and the (Round the answer to 3 PVA Compute the P-value of the test statistic: P-value is PVA Is the P-value less than the significance level? have sufficient evidence to reject the null 11:19 AM 7/11/2020
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