A person who weighs 744 N steps onto a spring scale in the bathroom, and the spring compresses by 0.510 cm.  What is the weight of another person who compresses the spring by 0.380 cm?

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ISBN:9781305952300
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Chapter1: Units, Trigonometry. And Vectors
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A person who weighs 744 N steps onto a spring scale in the bathroom, and the spring compresses by 0.510 cm.  What is the weight of another person who compresses the spring by 0.380 cm?

Expert Solution
Step 1

Given

  • The weight of the of a first-person is F=744 N.
  • The spring is compressed by the first person is x=0.510 cm=0.510 ×10-2 m.
  • The spring is compressed by the second person is x'=0.380 cm=0.380 ×10-2 m.

The force applied by the person is equal to its weight as he steps up on the spring. Therefore the force applied on the spring by first person is calculated as,

F=kx

Here, k is the spring constant.

Substitute the known values.

744 N=k×0.510×10-2 m....(i)

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