A person travels on a ski lift (Figure P4.82). Ca)lf you consider the person and chair as your object, what is Newton's 2nd law for the y-direction (assume vertically upward is positive)? Incorrect |Fr| Sin(8) - mg + |Fy| = 0 Incorrect |Fr| Cos(0) - mg + FN = 0 Incorrect |Fr| Sin(8) - mg = 0 Correct: |Fr| Cos(0) - mg = 0 You are correct. Your receipt no. is 150-1556 Prevlous Tries (b)What is Newton's 2nd law for the x-direction? Correct: |Frl Sin(0) = ma, Incorrect mg = ma, Incorrect |Fr = ma, Incorrect |FI - mg - ma, You are correct. Your receipt no. is 150-1060 O Previous Tries (C) If the support strut on the ski lift makes an angle 0 18°, what is the horizontal acceleration of the person? Submit Answor Tries 0/5 (d) If the person plus the lift chair have a combined mass m = 118 kg, what is the tension force along the support strut? Assume the ski lift is moving horizontally. For simplicity, when considering forces involving the support strut, you can treat the strut in the same way as you would treat a massless cable. Submit Answer Tries 0/5
A person travels on a ski lift (Figure P4.82). Ca)lf you consider the person and chair as your object, what is Newton's 2nd law for the y-direction (assume vertically upward is positive)? Incorrect |Fr| Sin(8) - mg + |Fy| = 0 Incorrect |Fr| Cos(0) - mg + FN = 0 Incorrect |Fr| Sin(8) - mg = 0 Correct: |Fr| Cos(0) - mg = 0 You are correct. Your receipt no. is 150-1556 Prevlous Tries (b)What is Newton's 2nd law for the x-direction? Correct: |Frl Sin(0) = ma, Incorrect mg = ma, Incorrect |Fr = ma, Incorrect |FI - mg - ma, You are correct. Your receipt no. is 150-1060 O Previous Tries (C) If the support strut on the ski lift makes an angle 0 18°, what is the horizontal acceleration of the person? Submit Answor Tries 0/5 (d) If the person plus the lift chair have a combined mass m = 118 kg, what is the tension force along the support strut? Assume the ski lift is moving horizontally. For simplicity, when considering forces involving the support strut, you can treat the strut in the same way as you would treat a massless cable. Submit Answer Tries 0/5
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Only need help for answers c and d.
Transcribed Image Text:NoFk U6 » Riding a Ski Lift
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A person travels on a ski lift (Figure P4.82).
(a)If you consider the person and chair as your object, what is Newton's 2nd law for the y-direction (assume vertically upward is positive)?
Incorrect |FT| Sin(0) - mg + FN = 0
Incorrect |FT| Cos(0) - mg + |FN| = 0
Incorrect |FT| Sin(0) - mg = 0
Correct: |FT | Cos(0) - mg = 0
You are correct.
Previous Tries
Your receipt no. is 150-1556 ?
(b)What is Newton's 2nd law for the x-direction?
Correct: |Fr| Sin(0) = ma,
Incorrect mg
Incorrect |FT| = ma,
Incorrect |FT\ - mg = maT
%3D
ma,
You are correct.
Your receipt no. is 150-1060
Previous Tries
(c) If the support strut on the ski lift makes an angle 0 = 18°, what is the horizontal acceleration of the person?
Submit Answer
Tries 0/5
118 kg, what is the tension force along the support strut? Assume the ski lift is moving horizontally. For simplicity, when considering forces involving the
(d) If the person plus the lift chair have a combined mass m =
support strut, you can treat the strut in the same way as you would treat a massless cable.
Submit Answer
Tries 0/5
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