12) A person drops a cylindrical steel bar (?=1.100×1011 Pa) from a height of 4.20 m (distance between the floor and the bottom of the vertically oriented bar). The bar, of length ?=0.780 m, radius ?=0.00600 m, and mass ?=2.000 kg, hits the floor and bounces up, maintaining its vertical orientation.Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Δ? of the bar? Use the gravitational acceleration ?=9.81 m/s2. A person drops a cylindrical steel bar (Y= 1.100 x 10'" Pa) from a height of 4.20 m (distance between the floor and thebottom of the vertically oriented bar). The bar, of length L =:0.780 m, radius R =0.00600 m, and mass m = 2.000 kg, hitsthe floor and bounces up, maintaining its vertical orientation.Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Al of thebar? Use the gravitational acceleration g9.81 m/s?.

(given) Y = 1.100×1011Pa Height = 4.20 m L = 0.780 m R = 0.00600 m m =2.000 kg g =9.81 m/s2 Using kinematics, velocity of the bar when it hits the ground v2 =v02+2adv2 =2adEnergy is conserved throughout.This means that the kinetic energy just before it hits the ground is equal to the stored potential energy when it fully compressed Kinetic energy = Potential energy Kinetic energy =12mv2 =12m(2ad) = madSpring potential energy , =12kx2F = kxk =F/x =YA/LFor potential energy, =1 2kx2 =1 2YAx2/L =12YπR2x2/LPotential energy = Kinetic energy 12YπR2x2/L = mad Maximum compression of the bar: ∆L or x = {2 mad L/[YπR2]} ={2 (2kg)(-9.8 m/s2)(4.20 m)(0.780m)/[(1.100×1011 Pa)π(0.00600m)2]} =9.1 ×10-7m

Answered: A person drops a cylindrical steel bar…

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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12) A person drops a cylindrical steel bar (?=1.100×1011 Pa) from a height of 4.20 m (distance between the floor and the bottom of the vertically oriented bar). The bar, of length ?=0.780 m, radius ?=0.00600 m, and mass ?=2.000 kg, hits the floor and bounces up, maintaining its vertical orientation.

Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Δ? of the bar? Use the gravitational acceleration ?=9.81 m/s2.

A person drops a cylindrical steel bar (Y
= 1.100 x 10'" Pa) from a height of 4.20 m (distance between the floor and the
bottom of the vertically oriented bar). The bar, of length L =
:0.780 m, radius R =
0.00600 m, and mass m = 2.000 kg, hits
the floor and bounces up, maintaining its vertical orientation.
Assuming that the collision with the floor is elastic and that no rotation occurs, what is the maximum compression Al of the
bar? Use the gravitational acceleration g
9.81 m/s?.

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