A pendulum with a cord of length r = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° ande = 270°, its speed is 4.60 m/s.(a)Find the magnitude of the radial acceleration (in m/s2) for these positions.m/s2(b)Find the magnitude of the tangential acceleration (in m/s2) for these positions.m/s2(c)Draw a vector diagram to determine the direction of the total acceleration for these two positions.aràа,0 = 900 = 270°0 = 90 °0 = 270atarArа,a,0 = 90°0 = 270°0 = 90°0 = 270°(d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration.magnitudem/s2direction• -Select-- v the horizontal10

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Description: A pendulum with a cord of length r = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° ande = 270°, its speed is 4.60 m/s.(a)Find the magnitude of the radial acceleration (in m/s2) for thes

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A pendulum with a cord of lengthr = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° and 0 = 270°, its speed is 4.60 m/s. (a) Find the magnitude of the radial acceleration (in m/s2) for these positions.

A pendulum with a cord of lengthr = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° and 0 = 270°, its speed is 4.60 m/s. (a) Find the magnitude of the radial acceleration (in m/s2) for these positions.

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Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

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Question

A pendulum with a cord of length r = 0.950 m swings in a vertical plane (see figure). When the pendulum is in the two horizontal positions e = 90° and
e = 270°, its speed is 4.60 m/s.
(a)
Find the magnitude of the radial acceleration (in m/s2) for these positions.
m/s2
(b)
Find the magnitude of the tangential acceleration (in m/s2) for these positions.
m/s2
(c)
Draw a vector diagram to determine the direction of the total acceleration for these two positions.
ar
à
а,
0 = 90
0 = 270°
0 = 90 °
0 = 270
at
ar
Ar
а,
a,
0 = 90°
0 = 270°
0 = 90°
0 = 270°
(d) Calculate the magnitude (in m/s2) and direction (in degrees above or below the horizontal) of the total acceleration.
magnitude
m/s2
direction
• -Select-- v the horizontal
10

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