In Fig.2, A Pelton wheel has a mean bucket speed (U) of 89 m/s with a jet of water flowing at the rate of 1 m3/s under a head of 270 m. The buckets deflect the jet through an angle of 170º. Calculate the power delivered to the runner and hydraulic efficiency of the turbine. Take Cv = 0.98 , V= Cv root of 2gH , workdone per second by the jet on the runner = ρaV1 (Vw1 + Vw2) x U and Hydraulic efficiency ηh = 2 U (Vw1 + Vw2)/V12 10:30 Allו. !ו O A1.8I81)K/sIms.abasynisb.edu.pk/ı44In Fig.2, A Pelton wheel has a meanbucket speed (U) of (last two digitsof your roll number) m/s with a jet ofwater flowing at the rate of 1 m3/sunder a head of 270 m. The bucketsdeflect the jet through an angle of170°. Calculate the power deliveredto the runner and hydraulic efficiencyof the turbine. Take Cy = 0.98 , V= Cvroot of 2gH , workdone per secondby the jet on the runner = paV1 (Vw1+ Vw2) x U and Hydraulic efficiencyNh = 2 U (Vw1+Vw2)/V,²EuK W2a270Angu-Vr1= VwqII

Given: U=89m/sec (U=U1=U2)Q=1m3/secDeflected…

Answered: A Pelton wheel has a mean bucket speed…

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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In Fig.2, A Pelton wheel has a mean bucket speed (U) of 89 m/s with a jet of water flowing at the rate of 1 m3/s under a head of 270 m. The buckets deflect the jet through an angle of 170º. Calculate the power delivered to the runner and hydraulic efficiency of the turbine. Take Cv = 0.98 , V= Cv root of 2gH , workdone per second by the jet on the runner = ρaV1 (Vw1 + Vw2) x U and Hydraulic efficiency ηh = 2 U (Vw1 + Vw2)/V12

10:30 A
llו. !ו O A
1.8
I81)
K/s
Ims.abasynisb.edu.pk/ı
44
In Fig.2, A Pelton wheel has a mean
bucket speed (U) of (last two digits
of your roll number) m/s with a jet of
water flowing at the rate of 1 m3/s
under a head of 270 m. The buckets
deflect the jet through an angle of
170°. Calculate the power delivered
to the runner and hydraulic efficiency
of the turbine. Take Cy = 0.98 , V= Cv
root of 2gH , workdone per second
by the jet on the runner = paV1 (Vw1
+ Vw2) x U and Hydraulic efficiency
Nh = 2 U (Vw1+Vw2)/V,²
EuK W2
a
270
Ang
u-
Vr1
= Vwq
II

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