A pellet gun is fired at a solid disk that is free to rotate about a fixed horizontal axis, as shown in Figure 8-63. The disk is 21 cm in diameter and has a mass of 370 g. The pellet (m = 30.0 g) gets lodged in the disk and causes it to spin at a rate of 11 rad/s. Find the speed of the pellet just before it hits the wheel.

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Chapter2: Vectors
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A pellet gun is fired at a solid disk that is free to rotate about a fixed horizontal axis, as shown in Figure 8-63. The disk is 21 cm in diameter and has a mass of 370 g. The pellet (m = 30.0 g) gets lodged in the disk and causes it to spin at a rate of 11 rad/s. Find the speed of the pellet just before it hits the wheel.

TR
12
10 = 29°
pellet
R
Figure 8-63 Problem 62.
Deduce from the given R/2 and
the radius of the circle R that the
angle is 30° in the right angled
triangle as shown.
1.
R
10 = 29° [ |2 30°
R
pellet
R
The position vector i goes from
the origin to the point where the
pellet hits the disk. Its magnitude
is R and its direction is known.
The angle between the position
vector i and the momentum
vector p can now be determined:
180° – 29° – 30° = 121°.
121°
10 = 29°
30°
pellet
R
Once the angle between vector ?
and vector p is determined, you
can find out the angular
momentum for the pellet:
L = rp sin 0 where 0 is the angle
between i and p.
3.
121°
p = mü
121°
2.
Transcribed Image Text:TR 12 10 = 29° pellet R Figure 8-63 Problem 62. Deduce from the given R/2 and the radius of the circle R that the angle is 30° in the right angled triangle as shown. 1. R 10 = 29° [ |2 30° R pellet R The position vector i goes from the origin to the point where the pellet hits the disk. Its magnitude is R and its direction is known. The angle between the position vector i and the momentum vector p can now be determined: 180° – 29° – 30° = 121°. 121° 10 = 29° 30° pellet R Once the angle between vector ? and vector p is determined, you can find out the angular momentum for the pellet: L = rp sin 0 where 0 is the angle between i and p. 3. 121° p = mü 121° 2.
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