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A patient order requires 1.6 L of a 0.4 % benzalkonium chloride antiseptic. You have a 11 % stock solution. Part A How much stock solution will you need to prepare the order? Express your answer to two significant figures and include the appropriate units. HA Value Units P Pearson

A patient order requires 1.6 L of a 0.4 % benzalkonium chloride antiseptic. You have a 11 % stock solution. Part A How much stock solution will you need to prepare the order? Express your answer to two significant figures and include the appropriate units. HA Value Units P Pearson

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A patient order requires 1.6 L of a 0.4 % benzalkonium chloride antiseptic. You have a 11 % stock solution. Part A How much stock solution will you need to prepare the order? Express your answer to two significant figures and include the appropriate units. HA Value Units P Pearson
Transcribed Image Text:A patient order requires 1.6 L of a 0.4 % benzalkonium chloride antiseptic. You have a 11 % stock solution. Part A How much stock solution will you need to prepare the order? Express your answer to two significant figures and include the appropriate units. HA Value Units P Pearson
<Ch08_Solutions Problem 8.43 - Enhanced - with Feedback How would you prepare 250 mL of a 0.225% (m/v) NaCl solution from a 0.85% (m/v) NaCl stock solution? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help 2.13 Add mL of the 0.85% NaCl stock solution to 56.25 66.2 250 mL of distilled water already measured in a flask distilled water for a total volume of 250 mL of solution P Pearson
Transcribed Image Text:<Ch08_Solutions Problem 8.43 - Enhanced - with Feedback How would you prepare 250 mL of a 0.225% (m/v) NaCl solution from a 0.85% (m/v) NaCl stock solution? Match the words in the left column to the appropriate blanks in the sentences on the right. Reset Help 2.13 Add mL of the 0.85% NaCl stock solution to 56.25 66.2 250 mL of distilled water already measured in a flask distilled water for a total volume of 250 mL of solution P Pearson
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