A past survey of 1,068,000 students taking a standardized test revealed that 8.5% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p, by using the following inequality. Assume the samples are random and independent. P,91 P292 -Z. n2 n2 °z+(d-d) > d- 'd> The confidence interval is
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- The following is a random sample of the annual salaries of high school counselors in the United States. Assuming that the distribution of salaries is approximately normal, construct a 99% confidence interval for the mean salary of high school counselors across the United States. Round to the nearest dollar. $47,860,$48,620,$64,020,$46,030,$52,360,$65,580,$40,620In a random sample of 800 men aged 25 to 35 years, 24% said they live with one or both parents. In another sample of 850 women of the same age group, 18% said that they live with one or both parents.A. Construct a 95% confidence interval for the difference between the proportions of all men and all women aged 25 to 35 years who live with one or both parents.B. Test at the 2% significance level whether the two population proportions are different.C. Repeat the test of part b using the p-value approach.A past survey of 1,068,000 students taking a standardized test revealed that 9.6% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, - P2 by using the following inequality. Assume the samples are random and independent. P191 + Zc P191 P292 P292A researcher surveyed college students in the United States on the typical amount of time each day that they spend interacting with different types of media (television, social media, Internet-connected devices, game consoles, etc.) The researcher found that the mean amount of time that college students spent watching television each day is 135 minutes with a 95% confidence interval of (105, 165). a. State the conclusion the researcher can make from this confidence interval. b. What is the margin of error for the confidence interval?A past survey of 1,068,000 students taking a standardized test revealed that 9.8% of the students were planning on studying engineering in college. In a recent survey of 1,476,000 students taking the SAT, 9.2% of the students were planning to study engineering. Construct a 90% confidence interval for the difference between proportions p, -p, by using the following inequality. Assume the samples are random and independent. A A P191 P292 + Zc n1 P11 P292In a poll of 7 randomly selected students showed that 31.3 % of the respondents believe in global warming. Based on the sample results, the margin of error E that corresponds to a 95% confidence level is equal to: O a. 0.45 O b. 0.34 O c. 0.29 O d. 0.22A statistics instructor randomly selected four bags of oranges, each bag labeled 10 pounds, and weighed the bags. They weighed 10.3, 10.8, 10.4, and 10.6 pounds. Assume that the distribution of weights is Normal. Find a 95% confidence interval for the mean weight of all bags of oranges. Use technology for your calculations. Answer parts a and b below. a. Choose the correct interpretation of the confidence interval below and, if necessary, fill in the answer boxes to complete your choice. A. We are 95% confident the population mean is between and B. There is a 95% chance that all intervals will be between and C. We are 95% confident that the sample mean is between and D. The requirements for constructing a confidence interval are not satisfied. (Type integers or decimals rounded to the nearest thousandth as needed. Use ascending order.)In a survey of 3242 adults aged 57 through 85 years, it was found that 82.9% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3242 subjects used at least one prescription medication? ____ (Round to the nearest integer as needed.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. ____%<p<____% (Round to one decimal place as needed.) c. What do the results tell us about the proportion of college students who use at least one prescription medication? A. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b). B. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b).…In a survey of3313 adults aged 57 through 85 years, it was found that 88.6% of them used at least one prescription medication. a. How many of the 3313 subjects used at least one prescription medication? (Round to the nearest integer as needed.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. (Round to one decimal place as needed.)In a poll of 515 human resource professionals, 45.8% said that body piercings and tattoos were big personal grooming red flags. Complete parts (a) through (d) below. a. Among the 515 human resource professionals who were surveyed, how many of them said that body piercings and tattoos were big personal grooming red flags? 236 (Round to the nearest integer as needed.) b. Construct a 99% confidence interval estimate of the proportion of all human resource professionals believing that body piercings and tattoos are big personal grooming red flags. Π (Round to three decimal places as needed.)Refer to the data set of 20 randomly selected presidents given below. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not? Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents. If greater height was an advantage, then taller candidates should have won (more than,less than,exactly) 50% of the elections. In this case, greater height (appears,does not appear) to be an advantage for presidential candidates because the confidence interval (does,does not) include 50%.Refer to the accompanying data set of 20 randomly selected presidents. Treat the data as a sample and find the proportion of presidents who were taller than their opponents. Use that result to construct a 95% confidence interval estimate of the population percentage. Based on the result, does it appear that greater height is an advantage for presidential candidates? Why or why not? Construct a 95% confidence interval estimate of the percentage of presidents who were taller than their opponents. PRESIDENT HEIGHT HEIGHT OPPMcKinley 170 178Lincoln 193 188Reagan 185 177Taft 182 178Harrison 173 168Van Buren 168 180Harding 183 178Eisenhower 179 178Taylor 173 174Garfield 183 187J. Kennedy 183 182Harrison 168 180J. Q. Adams 171 191Clinton 188 188Nixon 182 180Johnson 192 180Hoover 182 180T. Roosevelt 178 175Buchanan 183 175Polk 173 185Recommended textbooks for youMATLAB: An Introduction with ApplicationsStatisticsISBN:9781119256830Author:Amos GilatPublisher:John Wiley & Sons IncProbability and Statistics for Engineering and th…StatisticsISBN:9781305251809Author:Jay L. DevorePublisher:Cengage LearningStatistics for The Behavioral Sciences (MindTap C…StatisticsISBN:9781305504912Author:Frederick J Gravetter, Larry B. 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