A part’s maximum Von Mises stress and materials are given below.  Determine for each of these conditions whether the part is safe or not. Material: Steel, Von Mises Stress: 31000 psi, Static Loading, Ultimate Strength = 80000 psi Material: Polystyrene, Von Mises Stress: 42000 psi, Static Loading, Ultimate Strength = 7500 psi Material: Aluminum, Von Mises Stress: 62000 psi, Repeated Loading, Ultimate Strength = 30000 psi

Q: An aluminum rod is rigidly attached between a steel rod and a bronze rod as shown in the figure.…

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Q: m

A: Applied tensile load = 330000 N = 330Kn Maximum Allowable Stress = 110 Mpa…

Q: 2.) Find also the principal stresses oi and oz and its orientations 0p1 and 0p2 from the x-axis.…

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Q: 3.33 The following data are obtained from a tensile test of a 12.7-mm-diameter aluminum specimen…

A: As per the Guidelines of Bartleby We are supposed to answer only first three subparts. Ultimate…

Q: The bar 1 consists of an aluminum cover and a brass core. The data is presented in the table.…

A: Please refer explanationExplanation:Step 1: Step 2: Step 3: Step 4:

Q: Which of the following is the best representation of the samples' (A and B) axial strains when…

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Q: 2. An aluminum alloy specimen with a radius of 0.28 in. was subjected to tension until fracture and…

A: The solution is given below:

Q: 3. (A). Define the terms shear stress and shear strain, illustrating your answer by means of a…

A: shear stress : Shear stress is a force that tends to distort a material by causing it to slip along…

Q: please solve the following problem with paper and pencil and please show the correct answer and step…

A: Given: L = 28 feetE = 29 x 103 ksi The column height at length L= 28 feet. To simplify calculations,…

Q: FOR A GIVEN SOIL SAMPLE, THE FOLLOWING ARE KNOWN. ES=2-74, MOIST UNIT WEIGHT = 20 6 kN/m²³, AND…

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Q: A steel rod with a cross-sectional area of 188 mm2 is stretched between two fixed points. The…

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Q: tion by the cross-sectional area. Is this approach t? To answer this question consider the loading

A: STress is the ratio of force to the cross -sectional area.

Q: Bronze A = 300mm? 2.00 m E = 83 GPa Steel 1.00 m A = 600mm? E = 200 GPa A 0.60m 1.00 m 1.00m ΜN kN

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Q: A 0.375 -in. thick rectangular alloy bar is subjected to a tensile load P by pins at A and B. The…

A: Given data in question  Load 11 kips Thick 0.375 inch Height 3 inch Strain in longitudinal and…

Q: Consider a metal bar 12.5 mm in diameter and 50 mm in length that is tested under uniaxial tension.…

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Q: Q- A cylindrical piece of steel, with a diameter of 60mm and length 100 mm, is subjected to an axial…

A: Given data- Diameter d=60 mm, Length L=100 mm, Axial compressive force=40,000 kg, Bulk modulus =…

Q: Problem # 4 A 4 in x 3 in steel block follows an elasto-perfectly plastic stress strain relation…

A: Calculate the modular ratio: m=modulus of elasticity of steelmodulus of elasticity of…

Q: The stress–strain diagram for a steel alloy having an original diameter of 0.5 in. and a gage length…

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Q: Determine the strain if stress value is 33 MPa and modulus of elasticity is 80 MPa

A: Given data : The value of stress σ=33 MPa The value of modulus of elasticity E=80 MPa   To find :…

Q: A rectangular steel block is 4 inches long in the x direction, 3 inches long in the y direction, and…

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Q: The tensile test was carried out on a steel bar of length 18 cm and a cross section of 18 mm in…

A: Schematic diagram of the given problem: Maximum permissible tensile stress σ=400 N/mm2 E=200×103…

Q: Sample: Malleable Steel (AISI 4145) Original Diameter: 6.14mm Gauge Length: 55 mm Final Length:…

A: Given data, Original diameter D = 6.14 mm Gauge length L = 55 mm

Q: 7. A solid aluminum cylinder is placed within an ASTM A501 steel tube as shown. Compute the stresses…

A: Given Data: The diameter of the solid aluminum cylinder is d1=3 in. The diameter of the steel tube…

Q: Normal stress is calculated dividing the reaction by the cross-sectional area. Is this approach…

A: Given data in question  Normal stress approach To find out  Discuss the given statement

Q: agram as neces

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Q: SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and…

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Q: A typlcal aluminum-alloy scuba diving tank Is shown. The outside diameter of the tank is 200 mm and…

A: Maximum shear stress in plane = pd/8t Where,  d = inner diameter  d = 200-2*12 = 176mm

Q: amplitude was 210 MPa. Compute the maximum and minimum stress. (Enter your answers to three…

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Q: Use the engineering stress strain diagram provided bclow to answer parts (A) to (H) below (the…

A: Brief concept introduction- Stress-strain curve- It represents the variation of strain (on the…

Q: An aluminum alloy cylinder with a diameter of 76 mm and a height of150 mm. is subjected to a…

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Q: Problem 4 The test data of the coupon tests of stainless steel alloys are given for three test…

A: Given, Stress strain data for three specimens    To find : Elastic modulus, Yield stress and yield…

Q: SITUATION. As shown in the figure below, a rigid bar with negligible mass is pinned at O and…

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Q: Question No.2 Figure P1.16 shows the stress-strain relations of metals A and B during ten- sion…

A: It is that point on stress-strain curve, till which stress is linearly varying with strain. As per…

Q: Example: tension test has been conducted on a specimen of steel (Lo=100 mm, Do-20mm) and the…

A: Note:- dear student as per Bartley guidelines we are supposed to answer only first 3 subparts.…

Q: 1. Titanium alloy with an elastic modulus of 107 GPa (15.5 x 106 psi) and an initial diameter of 3.8…

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Q: fracture. Determine the following for the two metals (show all calculations and units): a.…

A: Stress vs strain curve is given. BY doing matriculation we can find the unknown.

Q: Q.3 The following data were obtained from the tensile test of Aluminum alloy. The initial diameter…

A: Given data; Gauge length = 2 in Initial diameter = 0.505 in

Q: If a steel has a value of oo = 150 MN/m² and k-0.70 MN/m³2, what are the values of yield stress for…

A: and yield stress of material                       Where,    is the constant value for a given…

Q: 90 alloy component as shown in following figure that is subjected to a stress of 200 MPa (29,000…

A: Given data stress= 200 MPa rupture lifetime be 509 h

Material Properties

Construction in civil engineering demands high strength, durability, and longevity. These targets can be achieved by better design and analysis, along with the correct choice of materials. Different materials have different properties and hence, they respond and performs differently under the various condition of external loadings. It is therefore a critical task of an engineer to select the right material based on the property that the material is supposed to function in real-time. When speaking about the property, there are different categories of material properties like chemical property, physical property, mechanical property, electrical property, magnetic property, thermal property, etc. These material properties form the basis of material selection in various applications.