A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8,000. A survey of owners of that tire design is conducted. Of the 28 tires surveyed, the mean lifespan was 46,800 miles with a standard deviation of 9,800 miles. Using alpha =0.05, is the data highly consistent with the claim? Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your lower and upper bounds to the nearest whole number.)
A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8,000. A survey of owners of that tire design is conducted. Of the 28 tires surveyed, the mean lifespan was 46,800 miles with a standard deviation of 9,800 miles. Using alpha =0.05, is the data highly consistent with the claim? Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label the point estimate and the lower and upper bounds of the confidence interval. (Round your lower and upper bounds to the nearest whole number.)
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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Transcribed Image Text:A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it
needs to be replaced. From past studies of this tire, the standard deviation is known to be 8,000.
A survey of owners of that tire design is conducted. Of the 28 tires surveyed, the mean lifespan
was 46,800 miles with a standard deviation of 9,800 miles. Using alpha =0.05, is the data highly
consistent with the claim?
Construct a 95% confidence interval for the true mean. Sketch the graph of the situation. Label
the point estimate and the lower and upper bounds of the confidence interval. (Round your lower
and upper bounds to the nearest whole number.)
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