A particle with mass m is moving in one dimension in the potential V(x). The particle is in a state of definite energy E, but it is not in a state of definite momentum p. Show that 2m +(V(x)) = E
A particle with mass m is moving in one dimension in the potential V(x). The particle is in a state of definite energy E, but it is not in a state of definite momentum p. Show that 2m +(V(x)) = E
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
Transcribed Image Text:3.5 A particle with mass m is moving in one dimension in the potential V(x). The particle
is in a state of definite energy E, but it is not in a state of definite momentum p. Show
that
(p²)
2m
+ (V(x))
= = E
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